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Verizon [17]
2 years ago
8

Help me please I WILL GIVE YOU BRAINLIEST PLEASEEE

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
5 0

Answer:

$42.50

Step-by-step explanation:

I'm pretty sure

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Evaluate <br><br> 0<br> ∫ ( 3^3 - 5^2) dx <br> -2
Jobisdone [24]
3^3 = 27
5^2 = 25
27 - 25 = 2

integral of 2 = 2x

(2x) evaluated from -2 to 0
= (0) - (2(-2)) = -(-4) = 4

If you did not make any mistakes in typing your question
the answer would be 4
4 0
3 years ago
16-25(b+3) square
Andre45 [30]
Since 16 and 25 are perfect squares you can factor the first part.
4^2-5^2(b+3)^2
=(4-5(b+3))(4+5(b+3))
=(4-5b-15)(4+5b+15)
=(-11-5b)(19+5b)

Which can be expanded if necessary,
= -209+150b-25b^2
4 0
3 years ago
Is 3 a divisor of 51?
Mariulka [41]
Answer:
Yes

Step by step explanation

5 0
2 years ago
Read 2 more answers
A rectangular vegetable patch has an area of 56 square meters and a
vredina [299]

Answer:

The dimensions of the vegetable patch is 8 m by 7 m.

Step-by-step explanation:

Area of a vegetable patch is 56 square meters and the perimeter is 30 m.

If l is length and b is breadth, then area and perimeter of a rectangle is given by :

A=l\times b

P=2(l+b)

Substituting the values in the above formulas as :

l\times b=56\ ....(1)

and

2(l+b)=30\\\\l+b=15\ .....(2)

We need to solve equation (1) and (2) to find the values of l and b such that :

Equation (2), l = 15 - b

Equation (1) becomes,

(15-b)b=56\\\\b=7\ m, 8\ m

If b = 7 m, so, l = 8 m

If b = 8 m, l = 7 m

So, the dimensions of the vegetable patch is 8 m by 7 m.

4 0
3 years ago
What is the value of X?
gayaneshka [121]

Answer:

45 i think

if not 54

8 0
2 years ago
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