3^3 = 27
5^2 = 25
27 - 25 = 2
integral of 2 = 2x
(2x) evaluated from -2 to 0
= (0) - (2(-2)) = -(-4) = 4
If you did not make any mistakes in typing your question
the answer would be 4
Since 16 and 25 are perfect squares you can factor the first part.
4^2-5^2(b+3)^2
=(4-5(b+3))(4+5(b+3))
=(4-5b-15)(4+5b+15)
=(-11-5b)(19+5b)
Which can be expanded if necessary,
= -209+150b-25b^2
Answer:
Yes
Step by step explanation
Answer:
The dimensions of the vegetable patch is 8 m by 7 m.
Step-by-step explanation:
Area of a vegetable patch is 56 square meters and the perimeter is 30 m.
If l is length and b is breadth, then area and perimeter of a rectangle is given by :


Substituting the values in the above formulas as :

and

We need to solve equation (1) and (2) to find the values of l and b such that :
Equation (2), l = 15 - b
Equation (1) becomes,

If b = 7 m, so, l = 8 m
If b = 8 m, l = 7 m
So, the dimensions of the vegetable patch is 8 m by 7 m.