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madreJ [45]
3 years ago
13

How to use discounts in our daily life?

Mathematics
2 answers:
Evgen [1.6K]3 years ago
8 0

Answer:

1.To calculate the discount, multiply the rate by the original price.

2.To calculate the sale price, subtract the discount from original price.

Hey mate hope its help you.....✨✨✨✨✨✨

Verdich [7]3 years ago
6 0

The basic way to calculate a discount is to multiply the original price by the decimal form of the percentage. To calculate the sale price of an item, subtract the discount from the original price. You can do this using a calculator, or you can round the price and estimate the discount in your head.
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Graph the equation using intercepts. <br> GIVING BRAINIEST TO WHOEVER HELPS ME AND GETS IT RIGHT
goldenfox [79]
Answer:

the line with go from the y-intercept -10 to the x-intercept 8

step-by-step explanation:
5x - 4y = 40
x = 0
5(0) - 4y = 40
-4y = 40
/-4 /-4
y = -10
y = 0
5x - 4(0) = 40
5x = 40
/5 /5
x = 8
the line with go from the y-intercept -10 to the x-intercept 8
7 0
3 years ago
Consider the function f(x)=−2/3x+1 <br> What is f(3)?
Oksana_A [137]
Replace x with 3 and simplify.
-1
Hope this helps! & Happy New Years! :)
5 0
3 years ago
The average of 10 numbers is -5. A new number is added to the list making the average-6. What is
DaniilM [7]

Question 1: The average of 10 numbers is -5. A new number is added to the list making the average -6. What is the new number?

To solve this question, first note that the sum of these numbers is -5*10 = -50. If the average of 11 numbers is -6, we must have that they add up to -6*11=-66. Therefore, the new number is -66-(-50) = -66+50 = -16.

Question 2: It is hard to explain why, but just know that the answer is No Solution. I think you must have made a typo, like maybe the product is -24?

7 0
3 years ago
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
Charlie has $12 saved already. He earns another $10 for each Tawn he mows. How many lawns must he mow to before he has $100 save
viva [34]

Answer:

8

Step-by-step explanation:

6 0
4 years ago
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