ANSWER
Phase shift: 2 units right.
EXPLANATION
The given sine function is

In mathematics, a horizontal shift may also be referred to as the phase shift.
This function is shifted to the right 2 units.
Answer:
We have function,

Standard Form of Sinusoid is

Which corresponds to

where a is the amplitude
2pi/b is the period
c is phase shift
d is vertical shift or midline.
In the equation equation, we must factor out 2 so we get

Also remeber a and b is always positive
So now let answer the questions.
a. The period is


So the period is pi radians.
b. Amplitude is

Amplitude is 6.
c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.
So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].
D. Plug in 0 for x.





So the y intercept is (0,-3)
E. To find phase shift, set x-c=0 to solve for phase shift.


Negative means to the left, so the phase shift is pi/4 units to the left.
f. Period is PI, so use interval [0,2pi].
Look at the graph above,
I think the answer is D because its multiplying by 2 each time
Answer:
The angles are <u>155°</u> and <u>25°</u>.
Step-by-step explanation:
Given:
Two supplementary angles are in the ratio of 31:5.
Now, to find the angles.
The sum of two supplementary angles = 180°
Let the ratio of the angles be
.
So, according to question:


<em>Dividing both sides by 36 we get:</em>

So, 
And, 
Therefore, the angles are 155° and 25°.
Answer:
14, 22
Step-by-step explanation:
x+y = 36
2×x - y = 6
=> x = 36 - y
=> 2×(36 - y) - y = 6
72 - 2y - y = 6
-3y = -66
3y = 66
y = 22
=> x = 36 - 22 = 14