Answer:
(a) Elongation of the rod==5.61×10⁻⁹m
(b) Change in diameter=1.640×10⁻⁸m
Explanation:
Given data
Diameter d=78 in=1.9812 m
Cross Area is:
Applied Load P=17 KN=17×10³N
E=29 × 106 psi=1.99947961×10¹¹Pa
Stress and Strain in x direction
Stress in x direction
σ=P/A
σ=5517.25 Pa
Strain in x direction
ε=σ/E
ε=2.76×10⁻⁸
Part (a)
Elongation of the rod=Lε
=(0.2032)(2.76×10⁻⁸)
Elongation of the rod==5.61×10⁻⁹m
Part(b) Change in diameter
Strain in y direction
ε₁= -vε
ε₁= -(0.30)(2.76×10⁻⁸)
ε₁=-8.28×10⁻⁹
Change in diameter=d×ε₁
Change in diameter=(1.9812m)×(-8.28×10⁻⁹)
Change in diameter=1.640×10⁻⁸m
The correct answer is option (C) the temperature of the shirt will increase because all wavelengths of light are absorbed by the shirt.
The relationship of heat and light
- Heat is a measure of the movement of particles in the body, the more particles move, the warmer the body becomes.
- When the body absorbs light radiation, its particles vibrate in accordance with the electromagnetic radiation's wavelengths, which causes an increase in the temperature with the increase in particle movement.
- The more wavelengths of radiation absorbed by an object, produces more heat.
Learn more about the Wavelength of light with the help of the given link:
brainly.com/question/13961990
#SPJ4
Answer:
True b and c
Explanation:
In an RLC circuit the impedance is
![Z = \sqrt{[R^{2} + ( (wL)^{2} + (\frac{1}{wC})^{2} ] }](https://tex.z-dn.net/?f=Z%20%3D%20%5Csqrt%7B%5BR%5E%7B2%7D%20%2B%20%28%20%28wL%29%5E%7B2%7D%20%2B%20%28%5Cfrac%7B1%7D%7BwC%7D%29%5E%7B2%7D%20%5D%20%20%20%20%20%7D)
examine the different phrases..
a) False. The maximum impedance is the value of the resistance
b) True. Resonance occurs when
(wL)² + (1 / wC)² = 0
w² = 1 / LC
c) True. In resonance the impedance is the resistive part and the power is maximum
d) False. In resonance the inductive and capacitive part cancel each other out
e) False. The impedance is always greater outside of resonance, but at the resonance point they are equal
Explanation:
Given that,
Initial speed of the sports car, u = 80 km/h = 22.22 m/s
Final speed of the runner, v = 0
Distance covered by the sports car, d = 80 km = 80000 m
Let a is the acceleration of the sports car. It can be calculated using third equation of motion as :
Value of g, 
Hence, this is required solution.
