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julia-pushkina [17]
3 years ago
10

Edgar is walking 0.5 M/S toward the back of a train that is traveling forward at 6.0 M/S west. What is Edgars velocity relative

to the ground?
Physics
1 answer:
iragen [17]3 years ago
8 0

Answer:

Just in 1 dimension  

Vpg = Vps + Vsg

Where

Vpg= relative to the ground

Vps= person relative to the ship

Vsg= ship relative to the ground

Vpg= Vps+Vsg ;

Vpg= 0.5 + 6  

Vpg= 6,5 m/s

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Answer:

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2 years ago
7. Un bloque de 700 N se encuentra sobre una viga uniforme de 200 N y 6 m de longitud. El bloque está a una distancia de 1 m del
GrogVix [38]

Answer:

 x =  0.176 m

Explanation:

For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.

Let's use trigonometry to decompose the tension

      sin 60 = T_{y} / T

      T_{y} = T sin 60

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      Tₓ = T cos 60

we apply the equation

       ∑ τ = 0

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the length of the bar is L = 6m

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             x = (6 T sin 60 - 3 M g) / mg

let's calculate

let's use the maximum tension that resists the cable T = 900 N

             x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)

             x = (4676 - 5880) / 6860

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Therefore the block can be up to 0.176m to keep the system in balance.

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Explanation:

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When an object moves in a straight line path, in this case, the displacement is equal to the distance traveled.

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