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julia-pushkina [17]

4 years ago

10

Edgar is walking 0.5 M/S toward the back of a train that is traveling forward at 6.0 M/S west. What is Edgars velocity relative

to the ground?

1 answer:

iragen [17]4 years ago

8 0

Answer:

Just in 1 dimension

Vpg = Vps + Vsg

Where

Vpg= relative to the ground

Vps= person relative to the ship

Vsg= ship relative to the ground

Vpg= Vps+Vsg ;

Vpg= 0.5 + 6

Vpg= 6,5 m/s

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lana66690 [7]

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3 years ago

In young’s double slit experiment, the measured fringe width is 0.5 mm for a Sodium light of 589 nm at a distance of 1.5 m. A br

Levart [38]

Answer:

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(B). The width of the bright fringe is 3.33 μm.

Explanation:

Given that,

Fringe width d = 0.5 mm

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Distance of screen and slit D = 1.5 m

Distance of bright fringe y = 1 cm

(A) We need to calculate the order of the bright fringe

Using formula of wavelength

$\lambda=\dfrac{dy}{mD}$

$m=\dfrac{d y}{\lambda D}$

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$m=5.65 = 6$

(B). We need to calculate the width of the bright fringe

Using formula of width of fringe

$\beta=\dfrac{yd}{D}$

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$\beta=\dfrac{1\times10^{-2}\times0.5\times10^{-3}}{1.5}$

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3 0

3 years ago

Mike walks 200 km in 6 hours.he then walks another 100km in 4 hours .what is his average speed?

kolbaska11 [484]

Average speed is defined as the ratio of total distance covered in total given time

$speed = \frac{distance}{time}$

here we know that total distance that man moved is

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$d_2 = 100 km$

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