Answer: The volume of an ideal gas will triple in value if the pressure is reduced to one-third of its initial value
Explanation:
We can determine this from the gas laws. Using Boyle's law, which states that "the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature"
Mathematically, P ∝ (1/V)
Since P ∝ (1/V), we can then write that
P = k(1/V)
Where P is the pressure, V is the volume and k is the proportionality constant
PV = k
We can then write that
P1V1 = P2V2 = P3V3 = ...
Hence, P1V1 = P2V2
Where P1 is the initial pressure of the gas
P2 is the final pressure of the gas
V1 is the initial volume of the gas
and V2 is the final volume of the gas
From the question, we want to determine what will make the new volume be thrice the initial volume.
Hence,
P1 = P
V1 = V
P2= ??
V2 = 3V
Therefore,
P × V = P2 × (3V)
P2 = PV/3V
P2 = P/3 = 1/3(P)
This means the volume of an ideal gas will triple in value if the pressure is reduced to one-third of its initial value
Answer:Your life is your responsibility.
Explanation:
A, because of the rule of action-reaction pairs
Answer:
α = 17.0 rad/s²
Explanation:
For this problem let's use the torque expression
τ = I α
Torque is the product of force by the distance that is half the length of the pencil
τ = F x
Let's use trigonometry
sin 10 = x / (l / 2)
x = l / 2 sin 10
τ = mg l /2 sin 10
The moment of inertia of pencil that we approximate as a rod with the axis of rotation at one end
I = 1/3 m L²
We replace
mg l / 2 sin 10 = 1/3 m l² α
α = 3/2 g/l sin 10
Let's reduce the magnitudes to the SI system
l = 15.0 cm = 0.150 m
m = 10.0 g = 0.0100 kg
Let's calculate
α = 3/2 9.8 / 0.150 sin 10
α = 17.0 rad/s²
Answer:
Destructive interference
Explanation:
Destructive interference occurs when waves come together in such a way that they completely cancel each other out. When two waves interfere destructively, they must have the same amplitude in opposite directions.