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2 years ago

How many of the elements of the periodic table are considered solids

Physics

1 answer:

Alex17521 [72]2 years ago

7 0

Answer:

There are two liquids, bromine and mercury, as well as eleven gases. The rest are solids, which is 105.

Explanation:

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The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground

kati45 [8]

Answer:

The time is 0.90 sec.

Explanation:

Given that,

Height = 4.00 m

We need to calculate the time

Using equation of motion

$s = ut-\dfrac{1}{2}(-g)t^2$

For free fall, u = 0

$t =\sqrt{\dfrac{2s}{g}}$

Where, s = distance

g = acceleration due to gravity

t = time

Put the value into the formula

$t =\sqrt{\dfrac{2\times4.00}{9.8}}$

$t= 0.90\ sec$

Hence, The time is 0.90 sec.

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2 years ago

Look at the figure, which shows the motion of three balls. The curved paths followed by balls B and C are examples of _____. pro

Natali [406]

Answer:did you get the answer?

Explanation:

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2 years ago

Read 2 more answers

If you walk 30 meters forwards, and then turn around and walk 25 meters backwards, what is the distance that you walked? What di

xeze [42]

Given :

Walk in forward direction is 30 m .

Walk in backward direction is 25 m .

To Find :

The distance and displacement .

Solution :

We know , distance is total distance covered and displacement is distance between final and initial position .

So , distance travelled is :

D = 30 + 25 m = 55 m .

Now , we first move 30 m in forward direction and then 25 m in backward direction .

So , displacement is :

D = 30 - 25 m = 5 m .

Therefore , distance and displacement covered is 55 m and 5 m respectively .

Hence , this is the required solution .

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2 years ago

An organ pipe open at both ends has a length of 0.80 m. If the velocity of sound in air is 340 m/s, what is the frequency of the

bazaltina [42]

Answer:

the frequency of the second harmonic of the pipe is 425 Hz

Explanation:

Given;

length of the open pipe, L = 0.8 m

velocity of sound, v = 340 m/s

The wavelength of the second harmonic is calculated as follows;

L = A ---> N + N--->N + N--->A

where;

L is the length of the pipe in the second harmonic

A represents antinode of the wave

N represents the node of the wave

$L = \frac{\lambda}{4} + \frac{\lambda}{2} + \frac{\lambda}{4} \\\\L = \lambda$

The frequency is calculated as follows;

$F_1 = \frac{V}{\lambda} = \frac{340}{0.8} = 425 \ Hz$

Therefore, the frequency of the second harmonic of the pipe is 425 Hz.

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2 years ago

A wire with a resistance R is lengthened to 3.07 times its original length by pulling it through a small hole. Find the new resi

charle [14.2K]

Explanation:

Below is an attachment containing the solution.

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2 years ago