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Alexus [3.1K]
3 years ago
8

How many of the elements of the periodic table are considered solids

Physics
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

There are two liquids, bromine and mercury, as well as eleven gases. The rest are solids, which is 105.

Explanation:

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One electron collides elastically with a second electron initially at rest. After the collision, the radii of their trajectories
morpeh [17]

Answer:

63.750KeV

Explanation:

We are given that

Initial velocity of second electron,u_2=0

Radius,r_1=0

r_2=2.3 cm=\frac{2.3}{100}=0.023 m

1 m=100 cm

Magnetic field,B=0.0370 T

We have to determine the energy of the incident electron.

Mass of electron,m=9.1\times 10^{-31} kg

Charge on an electron,q=-1.6\times 10^{-19} C

Velocity,v=\frac{Bqr}{m}

Using the formula

Speed of electron,v_1=\frac{Bqr_1}{m}=\frac{0.0370\times 1.6\times 10^{-19}\times 0}{9.1\times 10^{-31}}=0

Speed of second electron,v_2=\frac{0.0370\times 1.6\times 10^{-19}\times 0.023}{9.1\times 10^{-31}}

v_2=1.5\times 10^8 m/s

Kinetic energy of incident electron=\frac{1}{2}mv^2_1+\frac{1}{2}mv^2_2

Kinetic energy of incident electron=0+\frac{1}{2}(9.1\times 10^{-31})(1.5\times 10^8)^2=1.02\times 10^{-14} J

Kinetic energy of incident electron=\frac{1.02\times 10^{-14}}{1.6\times 10^{-19}}=63750eV=\frac{63750}{1000}=63.750KeV

1KeV=1000eV

3 0
3 years ago
How do l calculate e<br> nergy
aivan3 [116]

The formula for energy of motion is KE = .5 x m x v^2

Ke= Kinetic Energy in Joules

m = Mass in Kilograms

v = Velocity in Meters per Second

4 0
3 years ago
A 2-kg bowling ball sits on top of a building that is 40 meters tall.
Dahasolnce [82]
The bowling ball is at rest, so it only has gravitational potential energy.

Ug = mgy
Ug = (2)(9.8)(40) = 784 J

Need any more help?
6 0
3 years ago
Read 2 more answers
Which temperature scale has no negative temperatures A. Celsius B. Joule C. Fahrenheit D. Kelvin
Brilliant_brown [7]
The Kelvin scale has no negatives on it.

Zero Kelvin is 'Absolute Zero', and nothing can get colder than that.
6 0
3 years ago
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G a magnetic field perpendicular to the plane of a wire loop is uniform in space but changes with time t in the region of the lo
Luden [163]

Answer:

e = Δφ / Δt     induced emf is proportional to enclosed flux

Also φ  = B * A      flux is proportional to area and enclosed field

If the induced emf e increases with time than the flux and hence the magnetic field is increasing with time  (replace B with G)

Since e = ΔG * A / Δt    if e is linear then G must also be linear and be proportional to the time

6 0
2 years ago
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