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3 years ago

–10 – (–3) = ????? PLEASE HELP

Mathematics

2 answers:

julsineya [31]3 years ago

7 0

Answer:

-7

Step-by-step explanation:

−10−(−3)

=−10−(−3)

=−10+3

=−7

Over [174]3 years ago

7 0

Answer:

-7

you're welcome

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For each equation choose a value for x and then solve

ss7ja [257]

Answer:

Step-by-step explanation:

For each equation choose a value for x and then solve to find the corresponding y value that makes that equation true.

5 0

3 years ago

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

3 years ago

Please help!! I’m so confused And please don’t use the link joke

bagirrra123 [75]

Answer:

15u + 141 = 420

Step-by-step explanation:

So basically we are modelling how much the coach is spending. Each player is given a uniform and a basketball

We can use 'u' as the cost of a single uniform

We can use 'b' as the cost of a single basketball

Since there is 15 players we must give a ball and uniform to each so

15u + 15b = 420

The problem gives us the cost of each basketball: 9.40

so now 15u + 15(9.4) = 420

15u + 141 = 420

8 0

3 years ago

Determine the quotient, q(x), and remainder, r(x) when

Vinvika [58]

ANSWER

Quotient:

$q(x) = 4 {x}^{2} + 3x + 2$

Remainder:

$r(x) = 3x + 1$

EXPLANATION

The given functions are

$f(x) = 12 {x}^{4} + 21 {x}^{3} + 31 {x}^{2} + 21x + 9$

and

$g(x) = 3 {x}^{2} + 3x + 4$

We want to find the remainder and quotient when f(x) is divided by g(x).

We perform the long division as shown in the attachment.

The quotient is

$q(x) = 4 {x}^{2} + 3x + 2$

The remainder is

$r(x) = 3x + 1$

5 0

3 years ago

Can someone explain these two math questions to me? −2 + 4 ⋅ 32 − 6 5 + 42 ÷ 2(3)

zepelin [54]

The first one would be 120 the second one would be 68

8 0

3 years ago

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