You can do this using synthetic division, which is the easiest way. If x - 2 = 0, then x = 2. That 2 will go outside the "box" and the leading coefficients of the terms in the polynomial will go inside the "box". 2 (1 -3 -10 24). Bring down the first number, the
1. Multiply that 1 by the 2 to get 2. Put that 2 up under the -3 and add to get
-1. Multiply that -1 by the 2 to get -2. Put that =-2 up under the -10 and add to get
-12. Multiply that -12 by the 2 to get -24. Put the -24 up under the 24 and add to get 0. That means that x - 2 is a factor of the polynomial. What's left, the bolded numbers, are the coefficients of a new polynomial that is one degree less than the polynomial you started with. In other words, when we divide your polynomial by x-2, you get

.
Answer:
You already wrote the equation
Step-by-step explanation:
The end behaviour of the polynomial graph is (b) x ⇒ +∝, f(x) ⇒ -∝ and x ⇒ -∝, f(x) ⇒ -∝
<h3>How to determine the end behaviour of the polynomial graph?</h3>
The polynomial graph represents the given parameter
This polynomial graph is a quadratic function opened downwards
Polynomial function of this form have the following end behaviour:
- As x increases, f(x) decreases
- As x decreases, f(x) decreases
This is represented as
x ⇒ +∝, f(x) ⇒ -∝ and x ⇒ -∝, f(x) ⇒ -∝
Hence, the end behaviour is (b)
Read more about end behaviour at
brainly.com/question/1365136
#SPJ1
Step-by-step explanation:

We use the Work formula to solve for the unknown in the problem which is W = F x d. First, we solve for the Net Force acting on the car. The Net Force is the summation of all forces acting on the object. For this case, we assume that Friction Force is negligible thus the Net Force is equal to:
F = mgsinα in terms of SI units and in terms of english units we have F = m(g/g₀)(sin α) where g₀ is the proportionality factor, 32.174 ft lb-m / lb-f s²
F = 2500 (32.174/32.174) (sin 12°) = 519.78 lb
W = Fd = 519.78 lb (400 ft) = 207912 ft - lb or 20800 ft-lb