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m_a_m_a [10]
3 years ago
8

Explain why rational exponenets are not defined when the denominator of the exponent in lowest terms is even and the base is neg

ative.
Mathematics
2 answers:
ch4aika [34]3 years ago
6 0
Assume x > 0 then (-x)^(1/2) = sqrt(-x) and we cant take sqaure roots of negative numbers.............yet

so (-3)^(1/4) is<span><span>−3</span><span>−−−</span>√4</span>which is not ok but<span><span>−3</span><span>−−−</span>√3</span>is fine
Leona [35]3 years ago
4 0
Such a square root of a negative base wouldn't be possible. Because two (or just even numbers in general) negative numbers will always equal a positive number when multiplied, the rational exponent would not be defined because it isn't possible to conclude with a negative answer. However, if the denominator of the rational exponent happened to be an odd number, the problem would be solvable. When the denominator is an odd number it allows for the base to be negative because three negatives multiplied together give a negative answer. If the denominator of the exponent is even and the base is negative, the rational exponent will not be defined because it isn't possible.
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A rectangular room is 11 feet by 18 feet. The ceilings are 10 feet high. If a gallon of paint covers 250 square feet. How many g
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2.32 gallons of paint

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5 0
4 years ago
A survey of 1,107 tourists visiting Orlando was taken. Of those surveyed:
Ira Lisetskai [31]

Answer:

602 tourists visited only the LEGOLAND.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the tourists that visited LEGOLAND

-The set B represents the tourists that visited Universal Studios

-The set C represents the tourists that visited Magic Kingdown.

-The value d is the number of tourists that did not visit any of these parks, so: d = 58

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of tourists that only visited LEGOLAND, A \cap B is the number of tourists that visited both LEGOLAND and Universal Studies, A \cap C is the number of tourists that visited both LEGOLAND and the Magic Kingdom. and A \cap B \cap C is the number of students that visited all these parks.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

There were 1,107 tourists suveyed. This means that:

a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,107

We start finding the values from the intersection of three sets.

The problem states that:

36 tourists had visited all three theme parks. So:

(A \cap B \cap C) = 36

72 tourists had visited both LEGOLAND and Universal Studios. So:

(A \cap B) + (A \cap B \cap C) = 72

(A \cap B) = 72 - 36

(A \cap B) = 36

79 tourists had visited both the Magic Kingdom and Universal Studios

(B \cap C) + (A \cap B \cap C) = 79

(B \cap C) = 79 - 36

(B \cap C) = 43

68 tourists had visited both the Magic Kingdom and LEGOLAND

(A \cap C) + (A \cap B \cap C) = 68

(A \cap C) = 68 - 36

(A \cap C) = 32

258 tourists had visited Universal Studios:

B = 258

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

258 = b + 43 + 36 + 36

b = 143

268 tourists had visited the Magic Kingdom:

C = 268

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

268 = c + 32 + 43 + 36

c = 157

How many tourists only visited the LEGOLAND (of these three)?

We have to find the value of a, and we can do this by the following equation:

a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,107

a + 143 + 157 + 58 + 36 + 32 + 43 + 36 = 1,107

a = 602

602 tourists visited only the LEGOLAND.

6 0
4 years ago
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