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mash [69]
2 years ago
7

How does an executive order differ from a statue?

Physics
1 answer:
ICE Princess25 [194]2 years ago
6 0

Answer: Executive Order on Protecting American Monuments, Memorials, and Statues against our country are public monuments, memorials, and statues.

Explanation: learned it last week

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Anthony walks to the pizza place for lunch. He walk 1km east, then 1km south and then 1km east again. What distance did he cover
Komok [63]

Answer:

Pizza pizzza pizza

Explanation:

little ceasrs

8 0
2 years ago
Thomas Newcomen was the first to produce a working steam engine. Why is the work of James Watt more widely known than the work o
LenaWriter [7]

Answer:

The steam engine of James watt is more efficient than Newcomen ans more suitable for the industrial revolution.

Explanation:

James Watt is more widely know for working steam engine because Watt has created better engine which is suitable for the industrial revolution. The steam engine of James watt is more efficient than Newcomen. Watt developed the condensing arrangement by using piston which lessen the initial pressure leading to effectively worked than Newcomen's

4 0
2 years ago
The gravitational attraction between two objects increases if
JulijaS [17]

Answer:

they are closer!!

Explanation:

Hope this helped!! :D

8 0
3 years ago
if the vapor's volume were to be incorrectly recorded as 125ml, how will this error affect the calculated molar mass of the unkn
diamong [38]
So base on your question that as if the vapors volume were to incorrectly recorded as 125ml, the effect of the error to calculate the molar mass is the same as the error in measuring the volume of the vapor. I hope you are satisfied with my answer and feel free to ask for more 
7 0
3 years ago
A traves de una manguera de 1 in de diámetro fluye gasolina con una velocidad media de 5ft/s ¿cuál es el gasto?
jonny [76]

Answer:

El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.

Explanation:

El gasto es el flujo volumétrico de gasolina (Q), medido en pies cúbicos por segundo, que sale de la manguera. Asumiendo que la velocidad de salida es constante, tenemos que el gasto a través de la manguera es:

Q = \frac{\pi}{4}\cdot D^{2}\cdot v (1)

Donde:

D - Diámetro de la manguera, medido en pies.

v - Velocidad medida de salida, medida en pies por segundo.

Si sabemos que D = \frac{1}{12}\,ft y v = 5\,\frac{ft}{s }, entonces el gasto de gasolina es:

Q = \frac{\pi}{4}\cdot \left(\frac{1}{12}\,ft \right)^{2} \cdot \left(5\,\frac{ft}{s} \right)

Q \approx 0.0273\,\frac{ft^{3}}{s}

El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.

6 0
2 years ago
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