Answer:
sorry I don't know
Explanation:
have a great time with your family and friends
Answer:
THE SPECIFIC HEAT OF THE ALLOY IS 0.9765 J/g K
Explanation:
Mass of alloy = 33 g
Initial temperature of alloy = 93°C
Mass of water = 50 g
Initail temp. of water = 22 °C
Heat capacity of calorimeter = 9.20 J/K
Final temp. = 31.10 °C
specific heat of alloy = unknown
specific heat capacity of water = 4.2 J/g K
Heat = mass * specific heat * change in temperature = m c ΔT
Heat = heat capcity * chage in temperature = Δ H * ΔT
In calorimetry;
Heat lost by the alloy = Heat gained by water + Heat of the calorimeter
mc ΔT = mcΔT + Heat capacity * ΔT
33 * C * ( 93 - 31.10) = 50 * 4.2 * ( 31.10 -22) + 9.20 * ( 31.10 -22)
33 * C * 61.9 = 50 * 4.2 * 9.1 + 9.20 * 9.1
2042.7 C = 1911 + 83,72
C = 1911 + 83.72 / 2042.7
C = 1994.72 /2042.7
C =0.9765 J/g K
The specific heat of the alloy is 0.9765 J/ g K
Energy diagram for and endothermic and exothermic reaction
Answer:
See explanation
Explanation:
On the pH scale acidity ranges from pH values of 0-6.9. Natural rain water is slightly acidic due to the presence of carbon dioxide in the atmosphere which is an anhydride of carbonic acid.
CO2(g) + H2O(l) -------> H2CO3(aq)
B. The equations that turn sulfur to sulfuric acid are;
S(l) + O2(g) -----> SO2(g)
2SO2(l) + O2(g) -----> 2SO3(g)
SO3(g) + H2SO4(l) -----> H2S2O7(l)
H2S2O7(l) + H2O(l) ----> 2H2SO4(l)
-
At pH 6, H^+ concentration = 1 * 10^-6 M
At pH 2, H^+ concentration = 1 * 10^-2 M
Hence;
1 * 10^-2/1 * 10^-6
= 10^4 times more acidic
it does not freeze in the fridge, merely turns to a solid state. how long would depend on how warm it was before you put it in the fridge.
