Answer:
The van't Hoff factor for sodium chloride in X is 1.9 .
Explanation:
Mass of liquid x = 950 g = 0.950 kg
When 282 g of glycine are dissolved in 950 g of a certain mystery liquid X.
Depression in freezing point of the solution
Molality of the solution = m
The van't Hoff factor for glycine (non ionic) in liquid X= i =1
The value of molal depression constant for liquid X:
..(1)
Now 282. g of sodium chloride are dissolved in the same mass of X.
Depression in freezing point of the NaCl solution
Molality of the NaCl solution = m'
The van't Hoff factor for NaCl(ionic) in liquid X= i'
i = 1.9007 ≈ 1.9
The van't Hoff factor for sodium chloride in X is 1.9 .
Answer:
More reactants and fewer products
Explanation:
If reaction is exothermic it add heat to the environment, so when we add more heat the reaction will move in opposite direction. So, more reactants and fewer products will be formed.
Density = Mass/Volume
d = .254/129.4
There would be four to five atoms left