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ryzh [129]
3 years ago
8

The chemical equation below summarizes cellular respiration. 6O2 + C6H12O6 à 6CO2 + 6H2O + energy The energy that is released by

cellular respiration is in the form of dark energy. solar energy. nuclear energy. chemical energy.
Chemistry
2 answers:
Kamila [148]3 years ago
8 0

Answer : Option D) Chemical energy.

Explanation : The chemical equation 6 O_{2} + C_{6}H_{12}O_{6} ----> 6 CO_{2} + 6H_{2}O + Energy

In this reaction it is clear that 6 molecules of oxygen when combines with one molecule of glucose it produces 6 molecules of carbon dioxide and 6 molecules of water along with the generation of energy.

This is a pure chemical energy transformation reaction, as from the chemicals the energy is getting generated. Therefore, It is oxygen and glucose which helps in generating the energy.

So, the energy that is released by cellular respiration is in the form of chemical energy.


Kay [80]3 years ago
4 0
Chemical energy is released from the breaking down of glucose.
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A sample of pure NO2NO2 is heated to 335 ∘C∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2N
Alborosie

Answer:

k_c = 1. 1 × 10⁻²

Explanation:

Given that:

Temperature = 335 ° C = (335+ 273)K = 608

Pressure = 0.750 atm

Volume = 1 Litre

number of moles of NO2 = ???

Rate Constant =0.0821 L atm /K/mol

Using the Ideal gas equation

PV = nRT

n = \frac{PV}{RT}

n = \frac{0.75*1}{0.0821*608}

n = 0.015

n = 1.5 × 10⁻² mole

Density = 0.525 g/L

The equation for the reaction can be illustrated as:

                     2NO2(g)         ⇌          2NO(g)         +         O2(g)

For the ICE table; we have:

 

Initial                 x                                   0                              0

Change            -2y                               + 2y                          +y

Equilibrium        (x - 2y)                        2y                             y

Total moles at equilibrium = (x-2y)+2y+y

= x + y moles

However,

1.5 × 10⁻² mole of the mixture has a mass of 0.525 g

i.e x + y moles = 1.5 × 10⁻² mole

Now, molar mass of 1 mole of NO2 = 46g/mol

Since number of moles = \frac{mass}{molar mass}

mass of (x-2y) moles = 46 × (x-2y) g

Molar mass of NO = 30 g/mol

Also, mass of NO = 2y × 30 = 60y

Molar mass of O2 = 32 g/mol

Mass of O2 = y × 32 = 32y

Total mass = ( 46x - 90y)+60y+32y = 0.525

46x = 0.525

x = \frac{0.525}{46}

x = 0.0114

x = 1.14 × 10⁻²

x + y moles = 1.5 × 10⁻²

y =  1.5 × 10⁻² -  1.14 × 10⁻²

y = 0.0036

y = 3.6 × 10⁻³

At equilibrium

[NO2] = ( 1.14 - 2(0.36))× 10⁻² = 4.2 × 10⁻³ M

[NO] = 2 ( 3.6 × 10⁻³)  = 7.2 × 10⁻³ M

[O2] = 3.6 × 10⁻³ M

k_c = \frac{[NO]^2[O_2]}{[NO_2]^2}

k_c = \frac{(7.2*10^{-3})^2(3.6*10^{-3})}{(4.2*10^-3)^2}

k_c = 0.011

k_c = 1. 1 × 10⁻²

4 0
3 years ago
Read 2 more answers
Which of the following physicists paved the path for experiments with subatomic particles with his discovery of the
Setler [38]

Answer: OJJ Thompson

Explanation:

6 0
3 years ago
What volume of a 4.5 m solution of phosphate is necessary to create a 80.0 ml stock of 2.0 m phosphate solution?
11Alexandr11 [23.1K]

Answer: V1 = 45.6 ml

Explanation:

This is a dilution process whereby the concentration of phosphate in the solution is being reduced from 4.5m to 2m. Meanwhile. In a concentration process, the concentration of the phosphate solution will be increased. It can be achieved by removing solvents.

The dilution equation will be used. The equation is as follows:

M1V1 = M2V2 where

V1 = Initial volume of phosphate solution.

M1 = Initial concentration of phosphate solution.

V2 =Final volume of phosphate solution.

M2 = Final concentration of phosphate solution .

From the information given,

M1 = 4.5

V1 = ?

M2 = 2.0

V2 = 80

4.5 × V1 = 2×80

4.5V1 = 160

V1 = 160/4.5

= 35.6 ml

3 0
3 years ago
How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-k
weeeeeb [17]
Ideal gas law: PV = nRT

P-pressure
V-volume
n-number of moles(m/M)
R-constant
T- temperature

State given info:
V=10L
T=298k
P=203kPa
R=8.31(only for kPa, for pressure at atm use 0.08206)

Sub in:
(203kPa)(10L)=n(8.31)(298)

Rearrange:
n= (203)(10) / (8.31)(298)
n = 0.819745mol in gas sample
8 0
3 years ago
According to the kinetic theory, collisions between molecules in a gas _____.
marin [14]
<span>One of the main tenets of kinetic molecular theory is the the molecules of gas conserve their kinetic energy perfectly when they collide with each other (or the walls of the container for that matter), thus keeping them in constant motion. Since this is the definition of then elastic collision (one in which kinetic energy is maintained), then the answer is "d. are perfectly elastic".</span>
4 0
3 years ago
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