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gregori [183]
4 years ago
8

Balancing out Fe +h2O fe3O4 +H2

Chemistry
1 answer:
Katyanochek1 [597]4 years ago
4 0
3Fe + 4H2O (yields) Fe3O4 + 4H2
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Molecules have Question 8 options: A) only kinetic energy. B) neither kinetic nor potential energy. C) only potential energy. D)
emmasim [6.3K]
The answer is C. only potential energy
6 0
3 years ago
Which law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions?
Elanso [62]

Ideal gas law

Explanation:

The ideal gas law relates the temperature, pressure, volume and the number of moles of a gas under perfect conditions.

The ideal gas law is a combination of:

    Boyle's law- "the volume of a fixed mass of gas varies inversely as the pressure changes if the temperature is constant"

   Charles's law - "the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant"

    Avogadro's law - "equal volumes of all gases at the same temperature and pressure contains equal number of molecules".

 The law gives:

                     PV = nRT

where:

   P is the pressure of the gas

   V is the volume of gas

    n is the number of moles

     T is the temperature

     R is the gas constant

Learn more:

Ideal gas law problems brainly.com/question/13064292

#learnwithBrainly

7 0
4 years ago
____ is an important nutrient for pregnant mothers.
Elanso [62]

Its all of the above.

- I took the test and mine is correct.

3 0
3 years ago
Assuming the same temperature and pressure for each gas, how many milliliters of carbon dioxide are produced from 16 0 mL of CO
aivan3 [116]

Answer:

V_{CO_2}=16.0mL

Explanation:

Hello,

In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:

2CO(g)+O_2(g)\rightarrow 2CO_2(g)

We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:

n_{CO}V_{CO}=n_{CO_2}V_{CO_2}

Thus, solving for the yielded volume of carbon dioxide we obtain:

V_{CO_2}=\frac{n_{CO}V_{CO}}{n_{CO_2}} =\frac{2mol*16.0mL}{2mol}\\ \\V_{CO_2}=16.0mL

Best regards.

7 0
3 years ago
All of the following are conductors of electricity except
butalik [34]
What are the choices?
7 0
4 years ago
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