1) mol fraction of gas X= 2/(6+2)=2/8=1/4
2) mol fraction of gas Y= 6/(6+2)=6/8=3/4
3) Partial pressure of X = 1/4*2.1 atm=0.53 atm
4) Partial pressure of Y = 3/4*2.1=1.6 atm
First, we apply the law of conservation of mass which states that the total mass in a system remains constant.
Therefore, there must be 5.00 g of sulfur and 4.99 g of oxygen in the product. Now, we determine the mass percentage using:
Mass % = (mass of sulfur x 100) / total mass of compound
Mass % = (5 * 100) / (5 + 4.99)
Mass % = 50.05%
The product contains 50.05% sulfur by mass.
I think air but if wrong sorry
Answer: sum of the pressure of the two gases present.
Explanation:
According to Dalton's law, the total pressure of a mixture of gases is the sum of individual pressures exerted by the constituent gases.
For example if there are there are two gases hydrogen and oxygen with individual pressure of 30 and 20 atm each. Then the total pressure in the container will be:
Thus

Thus if two gases are present in a container, the total pressure in the container is equal to sum of the pressure of the two gases present.