The mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.
Volume = 45.0 L
Temperature = = (87.0 + 273) K = 360 K
Pressure = 950 mm Hg (1 mm Hg = 0.00131579 atm) = 1.25 atm
The formula used to calculate moles is as follows.
∴PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into the above formula as follows:
∴ PV = nRT
=> 1.25 atm × 45.0 L = n × 0.0821 L atm/mol K × 360K
=> n = 1.25 atm × 45.0 L / n × 0.0821 L atm/mol K × 360K
=> n = 56.25 / 29.556 mol
=> n = 1.90 mol
Moles is the mass of a substance divided by its molar mass. So, the mass of Cl₂ (molar mass = 70.906 g/mol) is calculated as follows:
∴ Moles = mass / molar mass
=> 1.90 mol = mass / 70.906 g/mol
=> mass = 134.7214 g
Thus, we can conclude that the mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.
To know more about the Ideal Gas Law :
brainly.com/question/28976906
The notation that is used to represent an alpha particle is 4.2 H [THAT IS, AN HELIUM ATOM].
Alpha particle is formed when a radioactive element undergoes an alpha radioactive decay. An alpha radioactive decay is the type of decay in which an atomic nucleus gives off an helium nucleus and is thereby transformed into another element, which has a mass number that is less than the original element. An alpha particle is an helium nucleus, which contains two positively charged proton and two neutral neutron; it has an overall charge of +2 and a mass number of 4.
Answer:
2.4 E-7 Kg/mL = 2.4 E5 μg/dm³
Explanation:
⇒ 2.4 E5 μg/dm³ * ( 1 E-6 g/μg ) * ( 1dm³/L ) * ( L/1000mL ) * ( Kg/1000g )
⇒ 2.4 E5 μg/dm³ = 2.4 E-7 Kg/mL
