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Burka [1]
3 years ago
8

What is the new volume of a sample of neon if 5.23 L of the gas, which was originally at 214 mmHg, is compressed until the press

ure increases to 796 mmHg?
Chemistry
1 answer:
Yuliya22 [10]3 years ago
8 0

This problem can be solved using Boyle's law:p1v1=p2v2

so 5.23*214=796*v2 v2=(5.23*214)/796=1.4L

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Individual measurements introduce errors that may be large or small depending on the quality of the tools and processes used. Sc
kirill [66]

Answer:

B. accepted value x 0.1

Explanation:

in the equation provided

Percentage Error=\frac{Error}{AcceptedValue} X100

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put this value in the equation in stead of percentage error we get,

10 = \frac{error}{AcceptedValue} X100\\ \frac{10}{100} =\frac{error}{AcceptedValue}\\.1=\frac{error}{AcceptedValue}\\error = .1 X Accepted Value

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8 0
3 years ago
How much heat is absorbed when a 298.3 g piece of brass goes from 30.0 to 150
igor_vitrenko [27]

Answer:

Q = 1360.248 j

Explanation:

Given data:

Mass of brass = 298.3 g

Initial temperature = 30.0°C

Final temperature = 150°C

Specific heat capacity of brass = 0.038 J/g.°C

Heat absorbed = ?

SOLUTION:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 150°C - 30.0°C  

ΔT = 120°C

Q = 298.3 g × 0.038 J/g.°C × 120°C

Q = 1360.248 j

3 0
3 years ago
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