How do I calculate the pOH of a Solution at 25℃ with a [OH-1] = 6.5 x 10-9 M and state whether the Solution is Acidic, Basic, or
1 answer:
You might be interested in
Explanation:
The net equation will be as follows.
So, we are required to find for this reaction.
Therefore, steps involved for the above process are as follows.
Step 1: Convert K from solid state to gaseous state
,
= 89 kJ
Step 2: Ionization of gaseous K
,
= 418 KJ
Step 3: Dissociation of gas into chlorine atom
.
,
= 122 KJ
Step 4: Iozination of chlorine atom.
,
= -349 KJ
Step 5: Add ion and
ion formed above to get KCl
.
,
= -717 KJ
Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.
= 89 + 418 + 122 - 349 - 717
= - 437 KJ/mol
Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.