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BartSMP [9]
3 years ago
9

How do I calculate the pOH of a Solution at 25℃ with a [OH-1] = 6.5 x 10-9 M and state whether the Solution is Acidic, Basic, or

Neutral?
Chemistry
1 answer:
morpeh [17]3 years ago
6 0

Answer:

pOH = 8.19

Acidic solution (pH < 7.0)

Explanation:

The pOH of the solution is defined as:

pOH = - log [OH⁻]

Since we have [OH⁻] = 6.5 x 10⁻⁹ M, we calculate the pOH as follows:

pOH = - log (6.5 x 10⁻⁹) = 8.19

To know if the solution is acidic, neutral or basic, we have to calculate the pH from the value of pOH:

pH + pOH = 14

⇒ pH = 14 - pOH = 14 - 8.19 = 5.81

The solution is acidic because pH < 7.0.

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Answer:

330.75 cm^3

Explanation:

d=m/v

10.5g/1 cm^3=31.5g/x cm^3

solve for x

round to the sig figs you have to.

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3 years ago
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Select all that apply: Select the benefits of sexual reproduction.
malfutka [58]
Sexual reproduction promotes adaptations, increases genetic diversity, and increases chances of survival. 
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4 years ago
A 1.40-L gaseous system absorbs 75 J of heat and expands its volume to 2.00 L against an external pressure of 1.02 atm. What is
kramer

Answer:

15.24 J is the change in internal energy for this process.

Explanation:

According to the first law of thermodynamics:-

\Delta U = q + w

Where,  

U is the internal energy

q is the heat

w is the work done

From the question,

q = + 75 J

(+ sign as the heat is being absorbed)

The expression for the calculation of work done is shown below as:

w=-P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

From the question,  

\Delta V = 2.00 - 1.40 L = 0.60 L

P = 1.02 atm

w=-1.02\times0.60\ atmL

Also, 1 atmL = 101.3 J

So,  

w=-1.02\times0.60\times 101.3\ J=-59.76\ J (work is done by the system)

So,

\Delta U = +75\ J-59.76\ J = 15.24\ J

<u>15.24 J is the change in internal energy for this process.</u>

6 0
3 years ago
A chemist must prepare 550.0 mL of nitric acid solution with a pH of 2.00 at 25 °C. He will do this in three steps: Fill a 550.0
WARRIOR [948]

Answer:

The correct answer is 0.61 ml

Explanation:

Nitric acid is a strong acid. That means that it dissociates completely in water as follows:

HNO₃ → H⁺ + NO₃⁻

As the dissociation is complete, the concentration of H⁺ ions is equal to the initial concentration of the acid (HNO₃). Thus, the pH can be calculated from the initial concentration of the acid:

pH= -log [H⁺] = -log  [acid]

We want a nitric acid solution with a pH of 2.0. so we first calculate the concentration of acid we need:

2.0 = -log [acid]

10⁻²=  [acid]

The chemist has a stock solution with C= 9.0 M and he/she wants a solution with C= 1 x 10⁻² M and V= 550 ml. We use the equation that relates the initial concentration and volume (Ci and Vi, respectively) of a solution with the final concentration and volume (Cf and Vf, respectively):

Ci x Vi = Cf x Vf

⇒ Vi= (Cf x Vf)/Ci = (1 x 10⁻² M x 550 ml)/9.0 M = 0.611 ml

Summarizing, the chemist must measure 0.611 ml of concentrated solution (9.0 M), add it to the flask and fill the flask to the mark until 550 ml in order to obtain a nitric acid solution with a pH of 2.0.

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4 years ago
_ Na3PO4 + _ HCl -&gt; NaCl + _ H3PO4
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