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Ostrovityanka [42]
2 years ago
15

You have a sample of 75.6 g of C3H8. How many moles of C3H8 are in the sample?

Chemistry
1 answer:
dsp732 years ago
3 0

The number of moles that are contained in the given mass of propane (C_3H_8 is 1.7143 moles.

<u>Given the following data:</u>

  • Mass of propane = 75.6 grams.

<u>Scientific data:</u>

  • The molar mass of propane = 44.1 g/mol.

To calculate the number of moles that are contained in the given mass of propane (C_3H_8):

<h3>How to calculate the moles of a compound.</h3>

In this exercise, you're required to determine the number of moles of propane that are contained in the given sample:

Mathematically, the number of moles contained in a chemical compound is given by this formula:

Number\;of\;moles = \frac{mass}{molar\;mass}

Substituting the given parameters into the formula, we have;

Number\;of\;moles = \frac{75.6}{44.1}

Number of moles = 1.7143 moles.

Read more on number of moles here: brainly.com/question/3173452

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If 1.2 moles of ideal gas occupy a volume of 18.2 L at a pressure of 1.8 ATM what is the temperature of gas in degrees Celsius.
Novosadov [1.4K]

Answer: A 59.5 degree celcius

The equation that we will use to solve this problem is :

PV = nRT where:

P is the pressure of gas = 1.8 atm

V is the volume of gas = 18.2 liters

n is the number of moles of gas = 1.2 moles

R is the gas constant =  0.0821

T is the temperature required (calculated in kelvin)

Using these values to substitute in the equation, we find that:

(1.8)(18.2) = (1.2)(0.0821)(T)

T = 332.5 degree kelvin

The last step is to convert the degree kelvin into degree celcius:

T = 332.5 - 273 = 59.5 degree celcius

8 0
3 years ago
What is kinetic energy of a 155 kg object moving at speed of 20 m/s
Novay_Z [31]

Answer:

KE = 1/2*m*v^2

KE = 1/2*150kg*(20 m/s)^2

KE = 75kg * 400m²/s²

KE = 30,000 kg*m²/s²

KE = 30,000 N*m

KE = 30,000 J

Explanation:

Hope this helped.

A brainliest is always appreciated.

4 0
2 years ago
Genetics and reproduction
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genetics and reproduction is all about dna.

7 0
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What type of reaction is shown below?
Lemur [1.5K]
<span>What type of reaction is shown below? 

2H2O2 → 2H2O + O2

A. synthesis
B. decomposition
C. combustion</span>decomposition

answer is B
8 0
3 years ago
Read 2 more answers
A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h
frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

Where;

\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

5 0
3 years ago
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