We are given –
- Mass of
is 57.1 g and we are asked to find number of moles present in 57.1 g of
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Now,Let's calculate the number of moles present in 57.1 g of
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Theoretical Yield is an Ideal yield with 100 % conversion of reactant to product. It is in fact a paper work.
While,
Actual Yield is the yield which is obtained experimentally. It is always less than theoretical yield because it is not possible to have 100% conversion of reactants into products. Even some amount of product is lost while handling it during the process.
Percentage Yield is Calculated as,
%age Yield = Actual Yield / Theoretical Yield × 100
Data Given:
Actual Yield = 0.104 g
Theoretical Yield = 0.110 g
Putting Values,
%age Yield = 0.104 g / 0.110 g × 100
%age Yield = 94.54 %
When given percents for an empirical formula problem, first consider all the percents as grams.
58.82% carbon —> 58.82 g carbon
27.45% nitrogen —> 27.45 g nitrogen
13.73% hydrogen —> 13.73 g hydrogen
Then convert the grams of all the elements to moles, based on their molar masses.
Carbon - 58.82 g / 12.01 g/mol = 4.898 mol carbon
Nitrogen - 27.45 g / 14.01 g/mol = 1.959 mol nitrogen
Hydrogen - 13.73 g / 1.008 g/mol = 13.62 mol hydrogen
Then divide all of the mole numbers by the smallest number of moles, which is in this case, the 1.959 mol of nitrogen.
Carbon - 4.898 / 1.959 = 2.5
Nitrogen - 1.959 / 1.959 = 1
Hydrogen - 13.62 / 1.959 = 7
You want whole numbers for all of your mole numbers, so multiply all of them by 2, since 2.5 isn’t a whole number.
Final answer: C5N2H14
