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Alona [7]
9 months ago
7

A student forgets to weigh a mixture of sodium bromide dihydrate and magnesium bromide hexahydrate. Upon strong heating, the sam

ple loses 252.1 mg of water. The mixture of anhydrous salts reacts with excess AgNO₃ solution to form 6.00X10⁻³ mol of solid AgBr. Find the mass % of each compound in the original mixture.
Chemistry
1 answer:
stira [4]9 months ago
4 0

The mass percent of each compound is

  • (NaBr*2H2O)=85.71 percent
  • (MgBr2*6H2O)=14.29 percent

<h3>The mass percent equation is as follows.</h3>

The formula mass percent is the most effective way to express mass percent: mass percent = (mass of chemical x total mass of compound) times 100. Add 100 to the top value to get the value expressed as a percentage.

<h3>What percentage by mass does a solution have?</h3>

By multiply the grams of solute per gram of solution by 100, it is possible to get the mass percent of a solution.

The molar mass of each element and the mass of each element contained in a mole of the compound are both solved for in the Mass Percent formula.

Learn more about Mass Percent here  

brainly.com/question/26150306

#SPJ4

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A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33
ANEK [815]

Explanation:

The given data is as follows.

     Vapour pressure of pure CCl_{4} = 33.85 Torr

         Temperature = 298 K

      Mole fraction of Br_{2} = 122.36 torr

Therefore, calculate the vapor pressure of Br_{2} as follows.      

     Vapour pressure of Br_{2} = mole fraction of Br_{2} x K of Br_{2}

                                    = 0.050 x 122.36 Torr

                                   = 6.118 Torr

So, vapor pressure of Br_{2} is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

     Vapour pressure of CCl_{4} = mole fraction of CCl_{4} x Pressure of CCl_{4}

                                     = (1 - 0.050) × 33.85 Torr

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So, vapor pressure of CCl_{4} is 32.1575 Torr  .

Hence, the total pressure will be as follows.

                         = 6.118 Torr + 32.1575 Torr

                         = 38.2755 Torr

Therefore, composition of CCl_{4} = \frac{32.1575 Torr}{38.2755 Torr}

                         = 0.8405

Composition of CCl_{4} is 0.8405 .

And, composition of Br_{2} = \frac{6.118 Torr}{38.2755 Torr}

                                                  = 0.1598

Composition of Br_{2} is 0.1598 .

6 0
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