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Alona [7]
1 year ago
7

A student forgets to weigh a mixture of sodium bromide dihydrate and magnesium bromide hexahydrate. Upon strong heating, the sam

ple loses 252.1 mg of water. The mixture of anhydrous salts reacts with excess AgNO₃ solution to form 6.00X10⁻³ mol of solid AgBr. Find the mass % of each compound in the original mixture.
Chemistry
1 answer:
stira [4]1 year ago
4 0

The mass percent of each compound is

  • (NaBr*2H2O)=85.71 percent
  • (MgBr2*6H2O)=14.29 percent

<h3>The mass percent equation is as follows.</h3>

The formula mass percent is the most effective way to express mass percent: mass percent = (mass of chemical x total mass of compound) times 100. Add 100 to the top value to get the value expressed as a percentage.

<h3>What percentage by mass does a solution have?</h3>

By multiply the grams of solute per gram of solution by 100, it is possible to get the mass percent of a solution.

The molar mass of each element and the mass of each element contained in a mole of the compound are both solved for in the Mass Percent formula.

Learn more about Mass Percent here  

brainly.com/question/26150306

#SPJ4

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Which choice can be a solid, liquid, or a gas?
Katena32 [7]

I believe that your option C would be the correct answer. We know that water can turn to a solid materail because during cold temperatures, water turns to ice.

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Assume that temperature and number of moles of gas are constant in this problem.
IrinaVladis [17]

Question:

a. a direct linear relationship

b. an inverse linear relationship

c. a direct nonlinear relationship

d. an inverse nonlinear relationship

Answer:

The correct option is;

d. An inverse nonlinear relationship

Explanation:

From the universal gas equation, we have;

P·V = n·R·T

Where we have the temperature, T and the number of moles, n constant, therefore, we have

P×V = Constant, because, R, the universal gas constant is also constant, hence;

P×V = C

P = \frac{C}{V}

Since P varies with V then the graphical relationship will be an inverse nonlinear as we have

V P    C

1 5         5

2 2.5      5

3 1.67     5

4 1.25     5

5 1          5

6 0.83    5

7 0.7      5

8 0.63    5

9 0.56    5

10 0.5      5

Where:

V = Volume

P = Pressure

C = Constant = 5

P = C/V

The graph is attached.

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