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djverab [1.8K]
3 years ago
9

Why does C-14 decay but not N-14?

Chemistry
1 answer:
Effectus [21]3 years ago
3 0

Beta decay occurs when a neutron transforms into a proton, an electron(and an electron anti-neutrino) Even though there are less electrostatically-repelling protons in C 14 than in N 14 the extra neutrons make the nucleus less stable than that of N 14

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Match the sequence number with the energy transformations from the water behind a hydroelectric dam to the lighting
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It’s 2 because trust me man it is
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Which statement about fusion is correct? Fusion creates radioactive waste. Fusion is the combining of small nuclei under extreme
Goshia [24]

Answer choice 'B' is correct.

#PlatoFam

6 0
3 years ago
Read 2 more answers
A 59.0 mL portion of a 1.80 M solution is diluted to a total volume of 258 mL. A 129 mL portion of that solution is diluted by a
julia-pushkina [17]

Answer:

0.170 M

Explanation:

As this is a <em>series of dilutions</em>, we can continuosly<em> use the C₁V₁=C₂V₂ formula </em>to solve this problem:

For the first step:

  • 59.0 mL * 1.80 M = 258 mL * C₂
  • C₂ = 0.412 M

Then for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:

  • V₂ = 129 mL + 183 mL = 312 mL

Using <em>C₁V₁=C₂V₂:</em>

  • 129 mL * 0.412 M = 312 mL * C₂
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4 0
3 years ago
What is the pressure of 0.33 moles of nitrogen gas, if its volume is 15.0 L at –25.0oC?
musickatia [10]

Using the ideal gas law PV =nRTPV=nRT , we find that the pressure will be P =\frac{nRT}{V}P=

V

nRT

​

 . Then, we'll substitute and find the pressure, using T = -25 °C = 248.15 K and R = 0.0821 \frac{atm\cdot L}{mol \cdot K}

mol⋅K

atm⋅L

​

 :

P =\frac{nRT}{V} = \frac{(0.33\,\cancel{mol})(0.0821\frac{atm\cdot \cancel{L}}{\cancel{mol \cdot K}})(248.15\,\cancel{K})}{15.0\,\cancel{L}} = 0.4482\,atmP=

V

nRT

​

=

15.0

L

​

(0.33

mol

)(0.0821

mol⋅K

atm⋅

L

​

​

)(248.15

K

​

)

​

=0.4482atm

In conclusion, the pressure of this gas is P=0.4482 atm.

Reference:

Chang, R. (2010). Chemistry. McGraw-Hill, New York.

3 0
1 year ago
You take a sample of water that is at room temperature and in contact with air and put it under a vacuum. Right away, you see bu
Artist 52 [7]

Answer:

The second friend is mostly correct.

Explanation:

When pressure decreases, gas solubility decreases. The bubbles are gas molecules that were dissolved in the water at atmospheric pressure. The bubbles started coming out as a result of the decrease pressure. The second bubbles would be water vapor because as the pressure continue to decrease, the amount of vapor pressure  ( vapor leaving the surface of the liquid ) equals the external pressure and water begin to boil. So the second bubbles must be water vapor.

7 0
3 years ago
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