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vazorg [7]
3 years ago
7

A balloon rubbed against denim gains a charge of −7.0 µc. what is the electric force between the balloon and the denim when the

two are separated by a distance of 3.0 cm? (assume that the charges are located at a point.) the value of the coulomb constant is 8.98755 × 109 n · m 2 /c 2 . include direction of the force. answer in units of n.
Physics
1 answer:
zubka84 [21]3 years ago
4 0
The solution for this problem is computed by through this formula, F = kQq / d²Plugging in the given values above, we can now compute for the answer.
F = 8.98755e9N·m²/C² * -(7e-6C)² / (0.03m)² = -489N, the negative sign denotes attraction.
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There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the co
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Answer:

0.208 N

Explanation:

We are given that

q_1=q_2=2.06\mu C=2.06\times 10^{-6} C

q_3=q_4=-2.06\mu C=-2.06\times 10^{-6} C

Distance,d=0.41 m

The magnitude of the net electrostatic force experienced by any charge at point 4

Net force,F_{net}=\sqrt{F^2_1+F^2_3+2F_1F_3cos90^{\circ}}-F_2

F_1=F_3=F

F_{net}=\sqrt{F^2+F^2+0}-F_2

F_{net}=\sqrt 2F-F_2

F=\frac{kq^2}{d^2}

F_2=\frac{Kq^2}{2d^2}

F_{net}=\frac{\sqrt 2kq^2}{d^2}-\frac{kq^2}{2d^2}=\frac{kq^2}{d^2}(\sqrt 2-\frac{1}{2})

Where k=9\times 10^9

F_{net}=\frac{9\times 10^9\times (2.06\times 10^{-6})^2}{(0.41)^2}(\sqrt 2-\frac{1}{2})

F_{net}=0.208 N

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Hot coffee in a mug cools over time and the mug warms up. Which describes the energy in this system?
givi [52]
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Gravity increased the downward speed (or decreases the upward speed) by 9.8 m/s every second.

21.2/9.8 = 2.2 seconds
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Answer:

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