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GuDViN [60]
3 years ago
5

A can cause a driver to take risky chances or make bad choices

Physics
1 answer:
Elena-2011 [213]3 years ago
8 0

-- loud radio
-- heavy rain
-- girl friend in the car
-- misguided sense of privilege or importance
-- misguided sense of immortality

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Because the earth's orbit is slightly elliptical, the earth actually gets closer to the sun during part of the year. When the ea
BabaBlast [244]

Closer to the sun . . . orbital speed is faster.

Farther from the sun . . . orbital speed is slower.

Flag answer:  Answer 13  Answer 13

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2 years ago
What effect would decreasing the distance between objects have on their gravitational attraction to each other?
Lady_Fox [76]
Decreasing the distance between two objects having a considerable mass would increase the attraction on gravitation. The reverse is true that if you separate or inrease the objects distance would substantially decrease their gravitational attraction. Most object in our planet is held by its gravitational force towards it's center.
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Power is your answer :)

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Find the velocity and distance travelled of a car that is accelerating at 3 m/s2 for 4 seconds.
marta [7]

Explanation:

Given:

v₀ = 0 m/s

a = 3 m/s²

t = 4 s

Find: Δx and v

Δx = v₀ t + ½ at²

Δx = (0 m/s) (4 s) + ½ (3 m/s²) (4 s)²

Δx = 24 m

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v = (3 m/s²) (4 s) + 0 m/s

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6 0
2 years ago
Consider the four quantum numbers of an electron in an atom, n, l, ml, and ms. The energy of an electron in an isolated atom dep
Effectus [21]

Answer:

The energy of an electron in an isolated atom depends on b. n only.

Explanation:

The quantum number n, known as the principal quantum number represents the relative overall energy of each orbital.

The sets of orbitals with the same n value are often referred to as an electron shell, in an isolated atom all electrons in a subshell have exactly the same level of energy.

The principal quantum number comes from the solution of the Schrödinger wave equation, which describes energy in eigenstates E_n, and for the case of an hydrogen atom we have:

E_n=-\cfrac{13.6}{n^2}\, eV

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