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vazorg [7]
3 years ago
7

Given the equation below, What is the reducing agent?

Chemistry
1 answer:
Scilla [17]3 years ago
6 0

Answer:

Reducing agent - S

Explanation:

The equation for the reaction is given as;

K2Cr2O3 + H2O + S --> SO2 + KOH + Cr2O3

The balanced equation is given as:

2K2Cr2O7 + 2H2O + 3S → 3SO2 + 4KOH + 2Cr2O3        

The reducing agent can be obtained by comparing the oxidation number of the elements. Increase in oxidation number signifies a reducing agent

K:

Reactant - 1

Product - 1

Cr

Reactant - +2

Product - +3

O

Reactant -   -2

Product -    -2

H

Reactant - +1

Product - +1

S

Reactant - O

Product - +4

S has an increase in oxidation number hence it is the reducing agent.

Although Cr has an increase in oxidation number, it occurs as a compound.

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Explanation:

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How many hydrogen bonds can CH2O make to water
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<span>H2C=O---------H-OH </span>

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3 years ago
For the galvanic (voltaic) cell Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s) (E°= 0.77 V at 25°C), what is [Fe2+] if [Mn2+] = 0.040 M and
avanturin [10]

Answer:

0.01836 M

Explanation:

Again the reaction equation is;

Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s)

E°cell= 0.77 V

Ecell= 0.78 V

[Mn2+] = 0.040 M

[Fe2+] = the unknown

n=2

From Nernst's equation;

Ecell= E°cell- 0.0592/n log Q

0.78= 0.77 - 0.0592/2 log [Fe2+] /[0.040]

0.78-0.77= - 0.0592/2 log [Fe2+] /[0.040]

0.01/ -0.0296= log [Fe2+] /[0.040]

-0.3378= log [Fe2+] /[0.040]

Antilog(-0.3378) = [Fe2+] /[0.040]

0.459= [Fe2+] /[0.040]

[Fe2+] = 0.459 × 0.040

[Fe2+] = 0.01836 M

7 0
4 years ago
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