2 answers:
The molar mass of the following compounds in two decimal places are as follows:
NH3 : 17.04 g/molMg(OH)2 : 58.33 g/molFe2O3 : 159.70 g/mol
<h3>MOLAR MASS:</h3>
The molar mass of a compound is the sum of all the atomic masses of the elements that constitutes the compound .
According to this question, three compounds were given as follows: NH3, Mg(OH)2 and Fe2O3.
The atomic mass of the elements in this compounds are as follows:
N = 14 H = 1 Mg = 24 O = 16 Fe = 56
The molar mass of NH3 = 14 + 3 = 17g/mol The molar mass of Mg(OH)2 = 24 + 32 + 2 = 58g/mol The molar mass of Fe2O3 = 56(2) + 16(3) = 160g/mol
Learn more about molar mass at: brainly.com/question/12127540
Determining Molar Mass
Use the periodic table to calculate the molar mass of each of the following compounds. Each answer must have 2 decimal places.
Answer:
- Ammonia ( NH 3 ): 17.04 g/mol is CORRECT :)
- Magnesium hydroxide (MG(OH)2): 58.33 g/mol is CORRECT :)
- Iron (lll) oxide (Fe2O3): 159.70 g/mol is CORRECT :)
Solution:
Got it right on EDGE. Hope this helps <3
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