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dem82 [27]
2 years ago
5

Determining Molar Mass

Chemistry
2 answers:
alisha [4.7K]2 years ago
6 0

The molar mass of the following compounds in two decimal places are as follows:

  • NH3: 17.04 g/mol
  • Mg(OH)2: 58.33 g/mol
  • Fe2O3: 159.70 g/mol

<h3>MOLAR MASS:</h3>

The molar mass of a compound is the sum of all the atomic masses of the elements that constitutes the compound.

According to this question, three compounds were given as follows: NH3, Mg(OH)2 and Fe2O3.

The atomic mass of the elements in this compounds are as follows:

  • N = 14
  • H = 1
  • Mg = 24
  • O = 16
  • Fe = 56

  1. The molar mass of NH3 = 14 + 3 = 17g/mol
  2. The molar mass of Mg(OH)2 = 24 + 32 + 2 = 58g/mol
  3. The molar mass of Fe2O3 = 56(2) + 16(3) = 160g/mol

Learn more about molar mass at: brainly.com/question/12127540

Sav [38]2 years ago
3 0

Determining Molar Mass

Use the periodic table to calculate the molar mass of each of the following compounds. Each answer must have 2 decimal places.

Answer:

- Ammonia ( NH 3 ): 17.04 g/mol is CORRECT :)

- Magnesium hydroxide (MG(OH)2): 58.33 g/mol is CORRECT :)

- Iron (lll) oxide (Fe2O3): 159.70 g/mol is CORRECT :)

Solution:

Got it right on EDGE. Hope this helps <3

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1,516.31168 grams of Magnesium Hydroxide

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Which of the following best describes a decomposition reaction?
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A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s
Lilit [14]

Answer:

pH = 1.32

Explanation:

                 H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount  to buffer solutions.  In the first  deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g  =  0.074 mol H₂M

54 mL x  1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH

it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.

For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

           

3 0
3 years ago
According to the rock cycle, which of the following transitions are possible? Assume an unlimited number of steps.
Vikentia [17]

(D)All of the above are possible.

Explanation:

According to the rock cycle, all of the transitions given are possible with several unlimited steps.

The rock cycle shows how the different rock types are transformed from one form to another.

In the rock cycle the major rock types are taken into consideration. These rock types are Igneous, sedimentary and metamorphic.

  • An intrusive igneous rock becomes a sedimentary rock.

Based on the rock cycle, an intrusive rock can become a sedimentary rock. This is igneous to sedimentary rock conversion. Here, the intrusive rock is brought during a terrain change to the surface. Weathering, erosion, transportation and deposition combines to produce sediments and take them to their basin of deposition where they form sedimentary rocks.

  • A sedimentary rock becomes soil.

By weathering, a sedimentary rock can be come a soil. Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soil.

  • A metamorphic rock becomes an extrusive igneous rock.

When metamorphic rocks are subjected to intense heat and pressure, they reach their melting point.

As they melt, they produce magma which can be brought to the surface to form extrusive volcanic rocks.

learn more:

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6 0
3 years ago
Which of the following Group 17 elements is the least reactive?
satela [25.4K]

The given question is incomplete. The complete question is :

Which of the following Group 17 elements is the least reactive

a) Flourine

b) Chlorine

c) Astatine

d) Iodine

Answer: c) Astatine

Explanation:

Halogen is the name given to Group 17 family with general electronic configuration of ns^2np^5 which have 7 valence electrons and thus easily gain one electron to attain stable configuration.

As we move down the group from flourine to chlorine to bromine to iodine to astatine , the valence shell moves farther from nucleus and thus tendency to accept the electron decreases and thus reactivity also decreases.

Thus Astatine is the least reactive of all.

7 0
3 years ago
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