Conduction-
putting an icepack on injury
grabbing a warm coffee mug
burning yourself by touching boiling water
the handle of a pot being to hot to touch
Convection-
heat from a fire to warm hands
warm water rising to the surface of of the ocean etc.
warm air rising off pavement
an oven that cooks by cycling warm air through the bottom and out the top
Radiation-
cooking popcorn using microwave
heat from the sun hitting a solar panel
( i havent done science in a while cuz im homeschooled but i think most of these are correct)
good luck on what your working on !!
Acacia ant and acacias animals are an example of coevolution
Coevolution is the reciprocal evolutionary change in a set of interacting population over time resulting from the interaction between those population and an example of coevolution that is not characteristics of an arm race but one which provides a mutual benefit to both a plant species and insect is that of the acacia ant and acacia plant and many cases of coevolution can be found between plants and insects
Know more about animal
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Answer:
C
Explanation:
Cause waves causes gravity to make higher waves
The idea here is that you need to figure out how many moles of magnesium chloride,
MgCl
2
, you need to have in the target solution, then use this value to determine what volume of the stock solution would contain this many moles.
As you know, molarity is defined as the number of moles of solute, which in your case is magnesium chloride, divided by liters of solution.
c
=
n
V
So, how many moles of magnesium chloride must be present in the target solution?
c
=
n
V
⇒
n
=
c
⋅
V
n
=
0.158 M
⋅
250.0
⋅
10
−
3
L
=
0.0395 moles MgCl
2
Now determine what volume of the target solution would contain this many moles of magnesium chloride
c
=
n
V
⇒
V
=
n
c
V
=
0.0395
moles
3.15
moles
L
=
0.01254 L
Rounded to three sig figs and expressed in mililiters, the volume will be
V
=
12.5 mL
So, to prepare your target solution, use a
12.5-mL
sample of the stock solution and add enough water to make the volume of the total solution equal to
250.0 mL
.
This is equivalent to diluting the
12.5-mL
sample of the stock solution by a dilution factor of
20
.