The _____ and _____ make up the nucleus. protons electrons ions neutrons nucleus

The fast server in women's tennis is Venus Williams, who recorded a serve of 130 (209 ) in 2007.

Gemiola [76]

Converting 209 km/hr to m/s:
209 km/hr = 58.0 m/s
Contact distance = 0.1 m

Using the equation of motion:
2as = v² - u², where initial velocity is 0

a = (58)² / (2 x 0.1)
a = 1.68 x 10⁴ m/s²

7 0

4 years ago

An object has a kinetic energy of 14 j and a mass of 17 kg how fast is the object moving

Brilliant_brown [7]

KE=14J
Mass=m=17kg
Velocity=v=?

$\\ \sf\Rrightarrow kE=\dfrac{1}{2}mv^2$

$\\ \sf\Rrightarrow 14=\dfrac{1}{2}17v^2$

$\\ \sf\Rrightarrow 17v^2=28$

$\\ \sf\Rrightarrow v^2=28/17$

$\\ \sf\Rrightarrow v^2=1.64$

$\\ \sf\Rrightarrow v\approx 0.13m/s$

5 0

3 years ago

Which marine habitats would have the least access to primary producers?

nikitadnepr [17]

Answer:

D

Explanation:

4 0

2 years ago

Which cars have the same magnitude of momentum? Check all that apply. car 1 car 2 car 3 car 4 car 5

wariber [46]

Answer:

Car 1 and Car 2 have the same momentum!

Explanation:

Using the formula of momentum (P=m*v), we get for each car:

Car 1: 5kg*2.2m/s = 11kg*m/s

Car 2: 5.5kg*2m/s = 11kg*m/s

Car 3: 6kg*1.35m/s = 8.1kg*m/s

Car 4: 6.5kg*1.9m/s = 12.35kg*m/s

Car 5: 7kg*1.25m/s = 8.75kg*m/s

7 0

3 years ago

A student measures the diameter of a small cylindrical object and gets the following readings: 4.32, 4.35, 4.31, 4.36, 4.37, 4.3

Zinaida [17]

Answer:

a. $\bar{d}=4.34 cm$

b. $\sigma=0.023 cm$

c. $\rho=(0.0089\pm 0.00058) kg/cm^{3}$

Explanation:

a) The average of this values is the sum each number divided by the total number of values.

$\bar{d}=\frac{\Sigma_{i=1}^(N)x_{i}}{N}$

$x_{i}$ is values of each diameter
N is the total number of values. N=6

$\bar{d}=\frac{4.32+4.35+4.31+4.36+4.37+4.34}{6}$

$\bar{d}=4.34 cm$

b) The standard deviation equations is:

$\sigma=\sqrt{\frac{1}{N}\Sigma^{N}_{i=1}(x_{i}-\bar{d})^{2}}$

If we put all this values in that equation we will get:

$\sigma=0.023 cm$

Then the mean diameter will be:

$\bar{d}=(4.34\pm 0.023)cm$

c) We know that the density is the mass divided by the volume (ρ = m/V)

and we know that the volume of a cylinder is: $V=\pi R^{2}h$

Then:

$\rho=\frac{m}{\pi R^{2}h}$

Using the values that we have, we can calculate the value of density:

$\rho=\frac{1.66}{3.14*(4.34/2)^{2}*12.6}=0.0089 kg/cm^{3}$

We need to use propagation of error to find the error of the density.

$\delta\rho=\sqrt{\left(\frac{\partial\rho}{\partial m}\right)^{2}\delta m^{2}+\left(\frac{\partial\rho}{\partial d}\right)^{2}\delta d^{2}+\left(\frac{\partial\rho}{\partial h}\right)^{2}\delta h^{2}}$

δm is the error of the mass value.
δd is the error of the diameter value.
δh is the error of the length value.

Let's find each partial derivative:

1. $\frac{\partial\rho}{\partial m}=\frac{4m}{\pi d^{2}h}=\frac{4*1.66}{\pi 4.34^{2}*12.6}=0.0089$

2. $\frac{\partial\rho}{\partial d}=-\frac{8m}{\pi d^{3}h}=-\frac{8*1.66}{\pi 4.34^{3}*12.6}=-0.004$

3. $\frac{\partial\rho}{\partial h}=-\frac{4m}{\pi d^{2}h^{2}}=-\frac{4*1.66}{\pi 4.34^{2}*12.6^{2}}=-0.00071$

Therefore:

$\delta\rho=\sqrt{\left(0.0089)^{2}*0.05^{2}+\left(-0.004)^{2}*0.023^{2}+\left(-0.00071)^{2}*0.5^{2}}$

$\delta\rho=0.00058$

So the density is:

$\rho=(0.0089\pm 0.00058) kg/cm^{3}$

I hope it helps you!

3 0

3 years ago