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2 years ago

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _ and the plate _.

Physics

1 answer:

Elan Coil [88]2 years ago

8 0

Answer:

Projected area= Diameter of the bolt* thickness.

Explanation:

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _Diameter of the bolt______ and the plate ___thickness____.

Projected area= Diameter of the bolt* thickness.

Projected area is a 2-dimensional area measurement of a 3-dimensional body by projecting its surface on an arbitrary plane

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a child in a tree house uses a rope attached to a basket to lift a 26 nn dog upward through a distance of 5.0 mm into the house.

agasfer [191]

Total work done is 0.13 Joules

The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force.

According to the given information

We need to find the work done

work done = force × distance

We are given,

force = 26 N

Distance = 0.0005 meter

hence ,

Work done = 26 × 0.005

= 0.13 Joules

Total work done is 0.13 Joules

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8 months ago

A bungee jumper feels weightless as she falls toward the earth.what accounts for her weightless feeling when she fall freely?1.

Ann [662]

The feel of weight comes due to the normal reaction force given by the support. Hence, the condition of weightlessness is when the normal reaction force becomes zero. So, during free fall there is no support which can provide the normal reaction. Hence, the bungee jumper feels weightless as she falls towards the earth because of the lack of support force that balances gravity.

Hence, the answer is 3.

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2 years ago

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harold threw a baseball 3 meters. harold is 2 meters tall. how fast did he throw the ball and how long was it in the air

Pepsi [2]

Answer:

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2 years ago

Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms

lakkis [162]

Answer:

(a) 333.77 J

(b) 237.85 J

(d) 4667.85 J

Explanation:

Temperature of source, TH = 314 K

Temperature of A, Tc = 292 K

Temperature of B, Tc' = 298 K

heat taken out, Qc = 4430 J

Let the heat deposited outside is QH and QH' by A and B respectively.

$\frac{Q_H}{Q_c}=\frac{T_H}{T_c}\\\\Q_H = \frac{4430\times314}{292}=4763.77 J$

Now

$\frac{Q_H'}{Q_c}=\frac{T_H}{T_c'}\\\\Q_H' = \frac{4430\times314}{298}=4667.85 J$

(a) Work done for A

W = QH - QC = 4763.77 - 4430 = 333.77 J

(b) Work done for B

W' = QH' - Qc = 4667.85 - 4430 = 237.85 J

(d) QH' = 4667.85 J

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2 years ago

Suppose you are helping Galileo measure the acceleration due to gravity by dropping a canon ball from the tower of Pisa, You mea

Anni [7]

It is given that the height of the tower is

$h=183 ft.$

The uncertainty the measurement of this height is

$\Delta h=0.2 ft$

Drop time is measured as:

$t=3.5s$

The uncertainty in measurement of time is:

$\Delta t=0.5 s$

Using the equation of motion: $h=ut+\frac{1}{2} at^2$ where, $h$ is the distance covered, $u$ is the initial velocity, $a$ is the acceleration and $t$ is the time.

$u=0$ (because canon ball is in free fall). we need to calculate the value of a=g.

$\Rightarrow h=\frac{1}{2}gt^2$

$\Rightarrow g=\frac{2h}{t^2}\\ \Rightarrow g=\frac{2\times 183ft}{(3.5s)^2}=29.87 ft/s^2$

The uncertainty in this value is given by:

$\Delta g=g\sqrt{(\frac{\Delta h}{h})^2+(\frac{2\Delta t}{t})^2}$

Substitute the values:

$\Delta g=29.87\sqrt{(\frac{0.2 }{183})^2+(\frac{2\times 0.5}{3.5})^2}=29.87\sqrt{1.19\times 10^{-6}+0.08}=29.87\times \sqrt{0.08}=29.87\times 0.28=8.44 ft/s^2$

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2 years ago

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _______ and the plate _______.

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _ and the plate _.