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2 years ago

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _ and the plate _.

Physics

1 answer:

Elan Coil [88]2 years ago

8 0

Answer:

Projected area= Diameter of the bolt* thickness.

Explanation:

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _Diameter of the bolt______ and the plate ___thickness____.

Projected area= Diameter of the bolt* thickness.

Projected area is a 2-dimensional area measurement of a 3-dimensional body by projecting its surface on an arbitrary plane

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A 0.10-kg ball, traveling horizontally at 25 m/s, strikes a wall and rebounds at 19 m/s. What is the 7) magnitude of the change

IRISSAK [1]

Answer:

Change in momentum will be -4.4 kgm/sec

So option (A) is correct option

Explanation:

Mass of the ball is given m = 0.10 kg

Initial velocity of ball $v_1=25m/sec$

And velocity after rebound $v_2=-19m/sec$

We have to find the change in momentum

So change in momentum is equal to $=m(v_2-v_1)=0.1\times (-19-25)=-4.4kgm/sec$ ( here negative sign shows only direction )

So option (A) will be correct answer

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3 years ago

Which amusement park ride utilizes periodic motion?

tatyana61 [14]

Any ride that oscillates back and forth or moves only in a complete circle utilizes periodic motion.

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2 years ago

5. How much time does it take for a bird flying at a speed of 45 kilometers per hour to travel a

Lyrx [107]

Answer:

$40h$

Explanation:

Use the velocity formula to solve

$v = \frac{d}{t}$

In this question, you are given velocity $v = 45km/h$ , and you are given a distance, $d = 1800km$ . Time in this question is what you'll need to find.

Start by rearranging the velocity formula, to isolate for t.

$v = \frac{d}{t}$

Start by multiplying both sides by t

$v(t) = \frac{d}{t}(t)\\\\vt = d$

Then divide both sides by v.

$vt\frac{1}{v} = d/v\\ \\t = \frac{d}{v}$

Now that you've isolated for time, sub in your values and calculate.

$t = \frac{d}{v} = \frac{1800km}{45km/h} = 40 h$

8 0

2 years ago

An object is located 50 cm from a converging lens having a focal length of 15 cm. Which of the following is true regarding the i

crimeas [40]

Answer:

It is real, inverted, and smaller than the object.

Explanation:

Let's start by using the lens equation to find the location of the image:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}$

where we have:

q = ? is the distance of the image from the lens

f = 15 cm is the focal length (positive for a converging lens)

p = 50 cm is the distance of the object from the lens

Solving the equation for q, we find

$\frac{1}{q}=\frac{1}{15 cm}-\frac{1}{50 cm}=0.047 cm^{-1}$

$q=\frac{1}{0.047 cm^{-1}}=+21.3 cm$

The sign of q is positive, so the image is real.

Now let's also write the magnification equation:

$h_i = - h_o \frac{q}{p}$

where

$h_i, h_o$ are the size of the image and of the object

By substituting p = 50 cm and q = 21.3 cm, we find

$h_i = - h_o \frac{21.3 cm}{50 cm}=-0.43 h_o$

So we notice that:

$|h_i| < |h_o|$ : this means that the image is smaller than the object

$h_i < 0$ : this means that the image is inverted

so, the correct option is:

It is real, inverted, and smaller than the object.

7 0

3 years ago

Pls answer this ,today is last day of classes then I got finals soon lol

KIM [24]

Answer and Explanation:

The law of conversation of energy states that energy cannot be created or destroyed. The pendulum slows down and stops eventually not because the kinetic energy is destroyed, but it is transferred into sound and heat energy instead because there is air resistance and friction.

Kinetic energy => Gravitational potential energy (Loop but some energy transferring to heat and sound each time)

4 0

2 years ago

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _______ and the plate _______.

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _ and the plate _.