All categories

2 years ago

When you stand on a bathroom scale, what force or forces are acting on you?

Chemistry

2 answers:

elena-s [515]2 years ago

5 0

B ......................

Readme [11.4K]2 years ago

3 0

Answer:

Explanation:

Lets see here, Gravity is pulling you down but your body is repelling to gravity. Meaning that gravity is pulling down your weight and the scale is reading it.

Hope this helped!

You might be interested in

A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula?

solong [7]

Answer:

C6H6 is the correct answer

5 0

2 years ago

Crabs are organisms that have five pairs of legs. In certain species of crabs, the fifth pair of legs has a flattened, paddle-li

Katyanochek1 [597]

Answer:

Explanation:

Crabs were exposed to a toxin in the water.

3 0

2 years ago

Determine the amount of heat (in kj) required to vaporize 1.55 kg of water at its boiling point. for water, δhvap

Usimov [2.4K]

Heat required to vaporize 1 mol of water from water at 100C to steam at 100C = 40.7 kJ
1 mol of water weighs = 18.015g
1.55 kg = 1550/18.015 mol = 86.03 mol

Heat required to vaporize :
= 86.03 mol x 40.7 kJ

= 3501.421 kJ

5 0

2 years ago

What charge would you expect for an formed by P?

Alex73 [517]

Answer:

friend according to the question the answer is +3 ....

6 0

2 years ago

Suppose we have a 12.2 L sample containing 0.50 mol oxygen gas at a pressure of 1 atm and a temperature of 25 degrees celcius. I

snow_lady [41]

Answer:

c. 8.1 L

Explanation:

Given that:-

Moles of oxygen gas = 0.50 mol

According to the reaction shown below as:-

$3O_2\rightarrow 2O_3$

3 moles of oxygen gas on reaction gives 2 moles of ozone

Also,

1 mole of oxygen gas on reaction gives 2/3 moles of ozone

So,

0.50 mole of oxygen gas on reaction gives $\frac{2}{3}\times 0.50$ moles of ozone

Moles of ozone = 0.3333 mol

Pressure = 1 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (25.0 + 273.15) K = 298.15 K

Volume = ?

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 0.3333 mol × 0.0821 L.atm/K.mol × 298.15 K

⇒V = 8.1 L

6 0

2 years ago