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lakkis [162]
3 years ago
7

PLS HELP

Chemistry
1 answer:
jeyben [28]3 years ago
3 0

Answer:

False

Explanation:

Negatively charged particles repel other negatively charged particles. Typically a negatively charged particle is electropositive and wants a positive molecule and/or cation (positive ion) to form a bond with. Negative molecules want positive molecules and vise versa.

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Why is feo named using a roman numeral, iron (ii) oxide, whereas cao named without a roman numeral, calcium oxide?
Hitman42 [59]
<span>Answer: Some metals have the ability to form differently charged ions. For example, iron can form 2 + or 3 + ions. If you simply gave the name iron chloride, you would not know which charge the iron ion possessed. A Roman numeral is to indicate the charge of the iron. Iron ( II ) means the iron has a 2 + charge Iron ( III ) means that the iron has a 3 + charge So, iron ( II ) oxide would have a chemical formula of FeO . (The oxide ion has a 2 â’ charge to balance the 2 + of the iron to form a neutral compound.) Iron ( III ) oxide would have a chemical formula of Fe 2 O 3 (Here you need to find the common multiple of 6, so two iron ions with a 3 + charge will balance the charge of three oxide ions with a 2 + charge.)</span>
7 0
3 years ago
Nitrogen gas reacts with hydrogen gas to produce ammonia. How many liters of hydrogen gas at 95kPa and 15∘C are required to prod
viktelen [127]

Answer:

222.30 L

Explanation:

We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:

Mass of NH₃ = 100 g

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 100 / 17

Mole of NH₃ = 5.88 moles

Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, Xmol of H₂ is required to p 5.88 moles of NH₃ i.e

Xmol of H₂ = (3 × 5.88)/2

Xmol of H₂ = 8.82 moles

Finally, we shall determine the volume (in litre) of Hydrogen needed to produce 100 g (i.e 5.88 moles) of NH₃. This can be obtained as follow:

Pressure (P) = 95 KPa

Temperature (T) = 15 °C = 15 + 273 = 288 K

Number of mole of H₂ (n) = 8.82 moles

Gas constant (R) = 8.314 KPa.L/Kmol

Volume (V) =?

PV = nRT

95 × V = 8.82 × 8.314 × 288

95 × V = 21118.89024

Divide both side by 95

V = 21118.89024 / 95

V = 222.30 L

Thus the volume of Hydrogen needed for the reaction is 222.30 L

8 0
3 years ago
If I have 5,000g of sodium, how much sodium sulfide can be made?
arlik [135]

2.469 could  be maid dont forget to hit that thanks button

8 0
3 years ago
Read 2 more answers
Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac
GalinKa [24]
<h2>a) The rate at which NO_2 is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen O_2 is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of NO = -\frac{1d[NO]}{2dt} = 0.066 M/s

Rate in terms of disappearance of O_2 = -\frac{1d[O_2]}{dt}

Rate in terms of appearance of NO_2= \frac{1d[NO_2]}{2dt}

1. The rate of formation of NO_2

-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}

\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s

2. The rate of disappearance of O_2

-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}

-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s

Learn more about rate law

brainly.com/question/13019661

https://brainly.in/question/1297322

7 0
3 years ago
How many p-orbitals are occupied in a Ar atom?
Orlov [11]

Answer:

6

Explanation:

p orbital can hold up to six electron. Argon electron configuration will be 1s²2s²2p⁶3s²3p⁶

6 0
3 years ago
Read 2 more answers
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