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Korvikt [17]
3 years ago
10

The molar solubility of ag2s is 1.26 × 10-16 m in pure water. calculate the ksp for ag2s.

Chemistry
1 answer:
MAXImum [283]3 years ago
6 0
Answer is: Ksp for silver sulfide is 8.00·10⁻⁴⁸.
Reaction of dissociation: Ag₂S(s) → 2Ag⁺(aq) + S²⁻(aq)<span>.
</span>s(Ag₂S) = s(S²⁻) = 1.26·10⁻¹⁶ M.
s(Ag⁺) = 2s(Ag₂S) = 2.52·10⁻¹⁶ M; equilibrium concentration of silver cations.
Ksp = s(Ag⁺)² · s(S²⁻).
Ksp = (2.52·10⁻¹⁶ M)² · 1.26·10⁻¹⁶ M.
Ksp = 6.35·10⁻³² M² · 1.26·10⁻¹⁶ M.
Ksp = 8.00·10⁻⁴⁸ M³.
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What are the magnitude (size) and direction of the cumulative force acting on the car shown in the picture A. 30 N to the right
UNO [17]

Answer: The correct answer is option(A).

Explanation:

Total forces exerting on the car = F

F_r=50 N= Force on car exerting in right direction

F_l=20 N= Force on car exerting in left direction

F_u=2500 N= Force on car exerting in upward direction

F_d=2500 N= Force on car exerting in downward direction

F=F_r+F_l+F_u+F_d

(-F_u)=F_d (negative sign shows the direction)

Since, upward force are equal in magnitude but opposite in direction by which they will balance out each other.so, the net force car will be due to two forces F_r and F_l

F=F_r+F_l=50 N+(-20 N)=30 N(negative shows the direction)

The magnitude (size) and direction of the cumulative force acting on the car will 30 N towards right direction.Hence, correct answer is option(A).

4 0
3 years ago
Read 2 more answers
Question 2 (10 points)
svet-max [94.6K]
4 infiltration percolation!! I think! Correct me if I’m wrong
6 0
3 years ago
What is the net ionic equation for 2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 6NaOH
tatuchka [14]

Answer:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

Explanation:

First of all, let us balance the equation to give;

2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 3NaOH

Now, we can observe the presence of positive Sodium ions (Na+) and negative hydroxyl ions (OH-) on both left and right sides of the equation.

Now, the two ions will cancel out. These ions are not really involved in the overall reaction and thus do not require being written in the overall equation. Hence, the overall net ionic reaction can now be written as:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

6 0
3 years ago
Calculate the number of moles in the following: 2.8 X 10^24 atoms of Cl2
vova2212 [387]

Answer:

<h3>The answer is 4.65 moles</h3>

Explanation:

To find the number of moles given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

n =  \frac{2.8 \times  {10}^{24} }{6.02 \times  {10}^{23}  }  \\  = 4.65116279069...

We have the final answer as

<h3>4.65 moles</h3>

Hope this helps you

7 0
3 years ago
How many moles are there in 24.00 g of NaCl
Elis [28]

Answer:

The answer to your question is 0.41 moles

Explanation:

Data

moles of NaCl = ?

mass of NaCl = 24 g

Process

To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.

1.- Calculate the molar mass

NaCl = 23 + 35.5 = 58.5 g

2.- Use proportions and cross multiplication

               58.5 g of NaCl ------------------- 1 mol

               24.0 g               ------------------- x

                     x = (24 x 1) / 58.5

                     x = 0.41 moles

6 0
3 years ago
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