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Korvikt [17]
3 years ago
10

The molar solubility of ag2s is 1.26 × 10-16 m in pure water. calculate the ksp for ag2s.

Chemistry
1 answer:
MAXImum [283]3 years ago
6 0
Answer is: Ksp for silver sulfide is 8.00·10⁻⁴⁸.
Reaction of dissociation: Ag₂S(s) → 2Ag⁺(aq) + S²⁻(aq)<span>.
</span>s(Ag₂S) = s(S²⁻) = 1.26·10⁻¹⁶ M.
s(Ag⁺) = 2s(Ag₂S) = 2.52·10⁻¹⁶ M; equilibrium concentration of silver cations.
Ksp = s(Ag⁺)² · s(S²⁻).
Ksp = (2.52·10⁻¹⁶ M)² · 1.26·10⁻¹⁶ M.
Ksp = 6.35·10⁻³² M² · 1.26·10⁻¹⁶ M.
Ksp = 8.00·10⁻⁴⁸ M³.
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The balanced reaction is 3 Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s ).

<u>Explanation</u>:

A chemical equation is said to be balanced when the total number of atoms present on the reactants side is equal to the total number of atoms present on the product side.

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