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emmasim [6.3K]
3 years ago
6

Antoine has a 100-gram sample of water in a sealed 1 liter container. He observes that when the water is moved to a sealed 2-lit

er glass container, it takes on the shape and volume of the new container. What best describes the sample water in it's current state?
Chemistry
2 answers:
elixir [45]3 years ago
7 0
Liquids form to the shape of every space they are put into.
Rzqust [24]3 years ago
5 0
Liquids take the shape of their containers.
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An element in group 7 on the periodic table most likely has which physical property?
larisa86 [58]

Answer:

They are most likely solid

Explanation:

solid is a physical property

3 0
3 years ago
What is the concentration of H+ in a 2.5 M HCl solution?
Pavel [41]

Answer:

The concentration of H⁺ in a 2.5 M HCl solution is 2.5 M

Explanation:

As HCl is a strong acid and hence a strong electrolyte, it will dissociate as

HCl ⟶ H⁺ + Cl⁻

So, The concentration of H⁺ will be 2.5 M (same as HCl)

Thus, The concentration of H⁺ in a 2.5 M HCl solution is 2.5 M

<u>-TheUnknownScientist</u><u> 72</u>

6 0
3 years ago
Read 2 more answers
1. A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C. If the
Maurinko [17]

Answer:

Mass of aluminium in sample = 3.591 g ≅ 3.6 grams

Explanation:

Given that,  A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C.

the specific heat of aluminum is 0.900 J/g- °C

The relation between heat absorbed and change in temperature is given by,   Q = msΔT.

where Q = heat absorbed

            m = mass of the substance

            s = specific heat of substance

          ΔT  = change in temperature

Now, in our case, Q = 50.1 J ; s = 0.900 J/g- °C; ΔT= 35.5-20 = 15.5°C

⇒ m =  \frac{Q}{s(T_{2} -T_{1}) }

⇒ m = \frac{50.1}{0.900(15.5)} = 3.591 g ≅ 3.6 g

⇒ m ≅ 3.6 g

5 0
3 years ago
Explain why magnesium bromide has a high melting point?
Neko [114]
Strong covalent bonds require significant energy to be broken?
7 0
3 years ago
A group of students perform three trials in a lab and determine the density of aluminum to be 2.1, 2.12, and 2.09 g/cm³ if the t
jenyasd209 [6]

Answer:

Percent error = -22%

Explanation:

Given data:

Density of aluminium = 2.1,2.12 and 2.09 g/cm³

Accepted value of density of aluminium = 2.7 g.cm³

Percent error = ?

Solution:

First of all we will calculate the average of data measured by students.

Average value = 2.1 g/cm³ + 2.12 g/cm³+ 2.09 g/cm³ / 3

Average value = 6.31 g/cm³/ 3

Average value = 2.1 g/cm³

Now we will calculate the percent error.

Percent error = [ Measured value - accepted value / accepted value ]× 100

Percent error = [ 2.1 g/cm³  - 2.70 g/cm³ / 2.70 g/cm³ ]× 100

Percent error = [-0.6/2.70 g/cm³ ] × 100

Percent error = -0.22 × 100

Percent error = -22%

4 0
3 years ago
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