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Anuta_ua [19.1K]

3 years ago

5

15. Explain how the atomic mass of an element is

1 answer:

vagabundo [1.1K]3 years ago

6 0

Answer:

The atomic mass of an element is affected by the distribution of its isotopes because each isotope of an element has a different number of neutrons in the nuclei of its atoms.

Explanation:

please give me brainlyiest if its right

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Organic compounds include

Norma-Jean [14]

Answer:

There are four main types or classes of organic compounds that are found in all living things. These are carbohydrates, lipids, proteins, and nucleic acids. ... All organic compounds contain carbon, usually bonded to hydrogen. Other elements may also be present.

Explanation:

5 0

3 years ago

I don't know the answer but I think that it is yes I just don't want to get it wrong

mrs_skeptik [129]

Yes your answer should be true.

8 0

3 years ago

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How much work must be done in the car to slow it from 100km/h to 50km/h

Brilliant_brown [7]

Answer:

$-96.465m$ joule

Explanation:

Let m = mass of the car and v1 = initial velocity and v2 = final velocity

Given.

Initial velocity = 100 km/h

final velocity = 50 km/h

What is work done in the car to slow it from 100km/h to 50km/h?

$v1=100km/h=27.78m/s$

$v2=50km/h=13.89m/s$

The work done in the car to slow it from v1 to v2.

w=Δk

$w=k2-k1$

$w= \frac{1}{2}m(v2)^{2}- \frac{1}{2}m(v1)^{2}$

$w=\frac{1}{2} m(v2-v1)^{2}$

$w=\frac{1}{2}\times m(13.89 -27.78)^{2}$

$w=\frac{1}{2}\times m(-13.89)^{2}$

$w=\frac{1}{2}\times m\times (-192.93)$

$w=-96.465m$ joule.

Therefore, the work done is $-96.465m$ joule

7 0

3 years ago

A microwave oven operating at 1.22 × 108 nm is used to heat 165 mL of water (roughly the volume of a teacup) from 23.0°C to 100.

ANTONII [103]

<u>Answer:</u> The number of photons are $3.7\times 10^8$

<u>Explanation:</u>

We are given:

Wavelength of microwave = $1.22\times 10^8nm=0.122m$ (Conversion factor: $1m=10^9nm$ )

To calculate the energy of one photon, we use Planck's equation, which is:

$E=\frac{hc}{\lambda}$

where,

h = Planck's constant = $6.625\times 10^{-34}J.s$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength = 0.122 m

Putting values in above equation, we get:

$E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{0.122m}\\\\E=1.63\times 10^{-24}J$

Now, calculating the energy of the photon with 88.3 % efficiency, we get:

$E=1.63\times 10^{-24}\times \frac{88.3}{100}=1.44\times 10^{-24}J$

To calculate the mass of water, we use the equation:

$Density=\frac{Mass}{Volume}$

Density of water = 1 g/mL

Volume of water = 165 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{165mL}\\\\\text{Mass of water}=165g$

To calculate the amount of energy of photons to raise the temperature from 23°C to 100°C, we use the equation:

$q=mc\Delta T$

where,

m = mass of water = 165 g

c = specific heat capacity of water = 4.184 J/g.°C

$\Delta T$ = change in temperature = $T_2-T_1=100^oC-23^oC=77^oC$

Putting values in above equation, we get:

$q=165g\times 4.184J/g.^oC\times 77^oC\\\\q=53157.72J$

This energy is the amount of energy for 'n' number of photons.

To calculate the number of photons, we divide the total energy by energy of one photon, we get:

$n=\frac{q}{E}$

q = 53127.72 J

E = $1.44\times 10^{-24}J$

Putting values in above equation, we get:

$n=\frac{53157.72J}{1.44\times 10^{-24}J}=3.7\times 10^{28}$

Hence, the number of photons are $3.7\times 10^8$

4 0

4 years ago

What is dispersion of light?

algol13

Answer:

$\huge \bold \blue{ \underline{ answer}}$

The splitting up of light into its constituent colours while passing from one medium to the other is called dispersion.

3 0

2 years ago

Read 2 more answers