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Basile [38]
2 years ago
7

A car starts from rest and moves along the positive x-axis with a constant acceleration of 5 m/s/s for 8 seconds. It then contin

ues with constant velocity, i.e. the velocity it attains at 8 seconds for the next 5 seconds. What will be the distance covered by the car in the first 12 seconds of its motion?
Physics
2 answers:
boyakko [2]2 years ago
8 0
Answer is 340 plz believe
tino4ka555 [31]2 years ago
5 0

Answer:

340

Explanation:

Because you are moving at 5 m/s^2 for 8 seconds, you need to do some arithmetic to get the distance covered in the beginning. TO do this, you do 5 + 5*2 + 5*3 + 5*4 + 5*5 + 5*6 + 5*7 + 5*8, and once you have passed eight seconds, you need 4 more seconds with constant velocity, or 4(5*8). Your final equation would be 5+10+15+20+25+30+35+40+40+40+40+40. Hope this helps!

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What is threshold frequency
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3 years ago
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Time period of a simple pendulum is measured at Karachi. What change will occur in the time period, if it is measured on mount e
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2 years ago
Find the resultant force of the following forces :
bezimeni [28]

The resultant of the given forces is; 6√2 N

<h3>How to find the resultant of forces</h3>

We are given the forces as;

10 N along the x-axis which is +10 N in the x-direction

6 N along the y-axis which is +6N in the y-direction

4 N along the negative x-axis which is -4N

Thus;

Resultant force in the x-direction is; 10 - 4 = 6N

Resultant force in the y-direction is; 6N

Thus;

Total resultant force = √(6² + 6²)

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Read more about finding resultant of a force at; brainly.com/question/14626208

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2 years ago
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The hydrogen stored inside a large weather balloon has a mass of 13.558 g. What is the volume of this balloon if the density of
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6 0
3 years ago
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A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the ground. How far, in meters, from the deck doe
Vesna [10]

Answer:

2.605m

Explanation:

Using the formula for calculating Range (distance travelled in horizontal direction)

Range R = U√2H/g

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g is the acc due to gravity = 9.8m/s²

R = 3.5m

Substitute into the formula and get H

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0.7292 = √2H/9.8

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H = 5.21/2

H = 2.605m

Hence the height of the ball from the ground is 2.605m

7 0
2 years ago
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