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lawyer [7]
2 years ago
8

A singly ionized helium atom is in the ground state. It absorbs energy and makes a transition to the n = 3 excited state. The io

n returns to the ground state by emitting two photons. What are their wavelengths?
Physics
1 answer:
IRISSAK [1]2 years ago
7 0

Answer:

\lambda=25.6nm

Explanation:

The Rydberg formula can be extended for use with any hydrogen-like chemical elements, that is to say with only one electron being affected by effective nuclear charge. So, in this case, we can calculate the wavelenghts of the emitted photons using this formula:

\frac{1}{\lambda}=RZ^2(\frac{1}{n_1^2}-\frac{1}{n_2^2})

Where R is the Rydberg constant of the element, Z its atomic number, n_1 is the lower energy level and n_2 the upper energy level of the  electron transition. Recall that the ground state is denoted as n=1.

\frac{1}{\lambda}=1.1*10^7m^{-1}(2)2^2(\frac{1}{1^2}-\frac{1}{3^2})\\\frac{1}{\lambda}=3.91*10^7m^{-1}\\\lambda=2.56*10^{-8}m=25.6nm

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Acceleration is generally defined as the time rate of change of velocity. When can it be defined as the time rate of change of s
Lena [83]

Answer:

When the velocity doesn't change its direction

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Since velocity vector has 2 components: direction and magnitude, and speed is the velocity's magnitude. So if the velocity doesn't change its direction, we essentially use its magnitude, aka speed, to calculate the rate of change for acceleration.

8 0
3 years ago
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Option d) abstraction is the correct answer.

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7 0
1 year ago
What property of matter determines how much inertia an object has
tester [92]
The mass of an object determines the object's inertia.
4 0
2 years ago
A wave with a frequency of 80 Hz travels through rubber with a wavelength of 7.0 m. What is the velocity of the wave?
Scorpion4ik [409]

Answer:

560 m/s

Explanation:

Given,

Frequency ( f ) = 80 hz

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Hence, the velocity of the wave is 560 m/s.

5 0
2 years ago
You are in a hot-air balloon that, relative to the ground, has a veloc- ity of 6.0 m/s in a direction due east. You see a hawk m
Ann [662]

Answer:

6.32 m/s 18.43° northeast

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We express the velocity of hawk as:

v_{Hawk}=v_{balloon}+v_{HawkRelativetoBalloon}=6 x+2 y

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