Answer:
-19
Step-by-step explanation:
Answer:
We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 31.7 milligrams
Sample mean, 
= 28.5 milligrams
Sample size, n = 9
Alpha, α = 0.05
Sample standard deviation, s = 2.8 milligrams
First, we design the null and the alternate hypothesis
We use One-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now, 
Since,
We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.
Answer:
equation 1
y = -2x
equation 2
y = x-3
Solution to both
(1,-2)
Step-by-step explanation:
We need to get the equations of both lines
General form is;
y = mx + c
where m is slope and c is the y-intercept
Table 1
since we have a point 0,0; the y-intercept here is zero
Let us get the slope. We can do this by selecting any two points
m = (y2-y1)/(x2-x1)
m = (2-10)/(-1+5) = -8/4 = -2
So the equation of the first line is;
y = -2x
Table 2
we get the slope
m = (4+2)/(7-1) = 6/6 = 1
The partial equation is;
y = x + c
To get c, we select any two point and substitute
4 = 7 + c
c = 4-7
c = -3
So the equation is;
y = x-3
To get the solution to both systems, we equate the y
-2x = x - 3
-2x-x = -3
-3x = -3
x = -3/-3
x = 1
To get y, we substitute;
recall; y = -2x
y = -2(1)
y = -2
Solution to the system is;
(1,-2)
Based on my knowledge, you’d set both equations equal to y, and then set both sides equal to each other then solve.
y=-5+x
y=-2x-4
-5+x=-2x-4
then solve from there
(this could be completely wrong, so don’t only go by my opinion)
Sam is using an industrial kitchen to make several batches of his famous chocolate chip granola bars. He needs to weight out 78 ounces of chocolate chips, plus or minus 2.5 ounces. The equation that can be used to find the minimum or maximum amount,c, of chocolate chips that he can weigh out is-
Absolute value equation is = |c-2.5| = 78
