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3 years ago

Match these equation balancing steps with the description of what was done in each step.

Mathematics

1 answer:

Alona [7]3 years ago

3 0

Step 1: C. Step 2: A Step 3: B

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£40 is divided between Jim, Krutika & Natasha so that Jim gets twice as much as Krutika, and Krutika gets three times as muc

harkovskaia [24]

Answer:Jim gets £24

Step-by-step explanation:

Let the amount Natasha gets be represented as x

SO that Krutika getting three times as much as Natasha be represented as 3x

AND Jim getting twice as much as Krutika be represented as 2 x 3x=6x

The equation to show how much each gets can be represented as

x + 3x +6x=40

Solving

x +3x + 6x=40

10x =40

x =40/10 =4

Natasha gets £4

Krutika gets 3x =3x4= £12

Jim gets 6x=6 x4= £24

7 0

3 years ago

I know the unit rate but don’t know the label.

guajiro [1.7K]

Miles per minute or miles per hour depending on how you did it.

7 0

3 years ago

Right to expressions for 45 minus n

trapecia [35]

Answer:

45-n

Step-by-step explanation:

i think this is what you mean

4 0

3 years ago

A travel agency has 2,106 people registered for a trip. Each tour bus can seat 54 people.

mariarad [96]

Answer:

39 buses

Step-by-step explanation:

2,106 ÷ 54 = 39

8 0

3 years ago

Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

$x^2(x-1)+x(x-1)-20(x-1)=0$

$(x-1)(x^2+x-20)=0$

Splitting the middle terms, we get

$(x-1)(x^2+5x-4x-20)=0$

$(x-1)(x(x+5)-4(x+5))=0$

$(x-1)(x+5)(x-4)=0$

Using zero product property, we get

$x-1=0\Rightarrow x=1$

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

3 0

3 years ago