7 organic compounds of plant origin

How many variance electrons in Aluminium? Is it 3

ololo11 [35]

Answer:

Question #1: How many valence electrons in Aluminum? Is it 3?

------> Yes, aluminum has 3 valence electrons.

Question #2: How many valence electron in Sulfur? Is it 6?

-----> Yes, sulfur has 6 valence electrons.

Question #3: What type of bonds do these form? Is it covalent or ionic?

-----> Covalent bonds generally occur between 2 nonmetals. Ionic bonds generally occur between a metal and a nonmetal. Aluminum is a metal and sulfur is a nonmetal. Therefore, an ionic bond would form.

Question #4: How many aluminum atoms will you need? 1, 2, or 3?

-----> Atoms become ions in order to achieve a full octet of valence electrons (8 valence electrons). Since aluminum atoms have 3 valence electrons, they are likely to donate these electrons during ionization. As such, aluminum ions look like this: Al³⁺. Since sulfur atoms have 6 valence electrons, they are likely to receive 2 electrons during ionization. As such, sulfur ions look like this: S²⁻.

-----> The ionic compound formed will be Al₂S₃. There would be 2 aluminum atoms because this arrangement allows for the ionic compound to have an overall charge of 0.

Aluminum = +3

Sulfur = -2

+3 + 3 + (-2) + (-2) + (-2) = 0

Question #5: How many sulfur atoms will you need? 1, 2, or 3?

-----> As stated previously the resulting ionic compound is Al₂S₃. There would be 3 sulfur atoms to balance the charges.

6 0

2 years ago

What is the mass defect of lithium? Assume the following:

Bumek [7]

Answer:

Δm = 3.0684

Explanation:

Data Given:

Atomic number of lithium = 3

Atomic mass of lithium = 7.0144 amu

Mass of 1 proton = 1.0073 amu

Mass of 1 neutron = 1.0087 amu

Solution:

Mass Defect:

Mass defect is the difference of mass number of an atom and its atomic number.

Formula used

Δm = [Z (mass of proton + mass of nutron) + ( A − Z ) mass of nutron] − m of atom

where:

Δm = mass defect (amu)

Z = atomic number

A = mass number

Put values in formula

Δm = [3 ( 1.0073 amu + 1.0087 amu) + ( 7 − 3 ) 1.0087 ] − 7.0144

Δm = [3 (2.016) + (4) 1.0087 ] − 7.0144

Δm = [(6.048) + (4.0348) ] − 7.0144

Δm = 10.0828 − 7.0144

Δm = 3.0684

7 0

3 years ago

Write about injector use in gas chromatography in detail. (don't copy from online sites )

KatRina [158]

Answer:

Gas chromatography is a common type of chromatography used in analytical chemistry for separating and analyzing compounds that can be vaporized without decomposition. Typical uses of GC include testing the purity of a particular substance, or separating the different components of a mixture. In preparative chromatography, GC can be used to prepare pure compounds from a mixture

as chromatography is a term used to describe the group of analytical separation techniques used to analyze volatile substances in the gas phase. In gas chromatography, the components of a sample are dissolved in a solvent and vaporized in order to separate the analytes by distributing the sample between two phases: a stationary phase and a mobile phase. The mobile phase is a chemically inert gas that serves to carry the molecules of the analyte through the heated column. Gas chromatography is one of the sole forms of chromatography that does not utilize the mobile phase for interacting with the analyte. The stationary phase is either a solid adsorbant, termed gas-solid chromatography (GSC), or a liquid on an inert support, termed gas-liquid chromatography (GLC).

Introduction

In early 1900s, Gas chromatography (GC) was discovered by Mikhail Semenovich Tsvett as a separation technique to separate compounds. In organic chemistry, liquid-solid column chromatography is often used to separate organic compounds in solution. Among the various types of gas chromatography, gas-liquid chromatography is the method most commonly used to separate organic compounds. The combination of gas chromatography and mass spectrometry is an invaluable tool in the identification of molecules. A typical gas chromatograph consists of an injection port, a column, carrier gas flow control equipment, ovens and heaters for maintaining temperatures of the injection port and the column, an integrator chart recorder and a detector.

To separate the compounds in gas-liquid chromatography, a solution sample that contains organic compounds of interest is injected into the sample port where it will be vaporized. The vaporized samples that are injected are then carried by an inert gas, which is often used by helium or nitrogen. This inert gas goes through a glass column packed with silica that is coated with a liquid. Materials that are less soluble in the liquid will increase the result faster than the material with greater solubility.The purpose of this module is to provide a better understanding on its separation and measurement techniques and its application.

Explanation:

Purpose of gas chromatography

The main purpose of the gas chromatography technique is to separate the compounds that possess:

High volatility
Low molecular weights
Thermal stability

8 0

3 years ago

What is the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution?

RoseWind [281]

Answer: 0.4M

Explanation:

Given that,

Amount of moles of NaOH (n) = ?

Mass of NaOH in grams = 40.0g

For molar mass of NaOH, use the atomic masses: Na = 23g; O = 16g; H = 1g

NaOH = (23g + 16g + 1g)

= 40g/mol

Since, n = mass in grams / molar mass

n = 40.0g / 40.0g/mol

n = 1 mole

Volume of NaOH solution (v) = 2.5 L

Concentration of NaOH solution (c) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

c = 1 mole / 2.5 L

c = 0.4 mol/L (Concentration in mol/L is the same as Molarity, M)

Thus, the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution is 0.4 mol/L or 0.4M

7 0

3 years ago

Thermal energy can be transformed to do work .<br> true<br> false

anyanavicka [17]

Answer:

FALSE!!! Thermal energy can be transformed to heat.

Explanation:

4 0

3 years ago

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7 organic compounds of plant origin​

7 organic compounds of plant origin