Answer:
Volume of oxygen gas is 78.47L
Explanation:
Data;
Temperature (T) = 20°C = (20 + 273.15)K = 293.15K
Pressure (P) = 0.919atm
Mass (m) = 5g
Volume (v) = ?
Equation of reaction;
4Fe + 3O₂ → 2Fe₂O₃
From the equation of reaction, the number of moles of oxygen is 3.
To find the volume of oxygen produced, we'll have to use ideal gas equation
PV = nRT
P = pressure
V = volume
n = number of moles
R = ideal gas constant = 0.082J/mol.K
T = temperature of the ideal gas
PV = nRT
V = nRT/ P
V = (3 × 0.082 × 293.15) / 0.919
V = 72.1149 / 0.919
V = 78.47L
Volume of the gas is 78.47L
