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3 years ago

What volume of oxygen gas at 20°C and 0.919 atm is

Chemistry

1 answer:

ehidna [41]3 years ago

5 0

Answer:

Volume of oxygen gas is 78.47L

Explanation:

Data;

Temperature (T) = 20°C = (20 + 273.15)K = 293.15K

Pressure (P) = 0.919atm

Mass (m) = 5g

Volume (v) = ?

Equation of reaction;

4Fe + 3O₂ → 2Fe₂O₃

From the equation of reaction, the number of moles of oxygen is 3.

To find the volume of oxygen produced, we'll have to use ideal gas equation

PV = nRT

P = pressure

V = volume

n = number of moles

R = ideal gas constant = 0.082J/mol.K

T = temperature of the ideal gas

PV = nRT

V = nRT/ P

V = (3 × 0.082 × 293.15) / 0.919

V = 72.1149 / 0.919

V = 78.47L

Volume of the gas is 78.47L

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Explanation:

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This trend is commonly attributed to the degree of π-bonding in the planar boron trihalide that would be lost upon pyramidalization (the conversion of the trigonal planar geometry to a tetrahedral one) of the BX3 molecule, which follows this trend: BF3 > BCl3 > BBr3 (that is, BBr3 is the most easily pyramidalized). The criteria for evaluating the relative strength of π-bonding are not clear, however. One suggestion is that the F atom is small compared to the larger Cl and Br atoms, and the lone pair electron in the 2pzorbital of F is readily and easily donated, and overlaps with the empty 2pz orbital of boron. As a result, the [latex]\pi[/latex] donation of F is greater than that of Cl or Br. In an alternative explanation, the low Lewis acidity for BF3 is attributed to the relative weakness of the bond in the adducts F3B-L.

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marishachu [46]

Answer: Pairs are: (a) and (d), (b) and (f), (c) and (e)

Explanation:

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

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The given electronic configuration is: $1s^22s^22p^63s^2$

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The number of valence electrons in the given configuration are [2 + 6] = 8

For d:

The given electronic configuration is: $1s^22s^2$

The number of valence electrons in the given configuration are 2

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The given electronic configuration is: $1s^22s^22p^6$

The number of valence electrons in the given configuration are [2 + 6] = 8

For f:

The given electronic configuration is: $1s^22s^22p^63s^23p^3$

The number of valence electrons in the given configuration are [2 + 3] = 5

Electronic configuration of (a) and (d) will form a pair, (b) and (f) will form a pair, (c) and (e) will form a pair and will have similar chemical properties.

Hence, the pairs are: (a) and (d), (b) and (f), (c) and (e)

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