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faltersainse [42]
2 years ago
10

Help me please this is very important to me for rbainlist and explain

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
6 0

Answer:

Step-by-step explanation:

The probability of getting one even and one odd is the sum of probability of getting even and of getting odd and even. Since there are 3 even or odd on each die out of six numbers you have

P(EO)(3/6)(3/6)=1/4 and P(OE)=(3/6)(3/6)=1/4 so 1/4+1/4= 1/2

or you can find the probability of getting two odds or two evens and subtract that from 1

P(EE)=(3/6)(3/6)=1/4, P(OO)=(3/6)(3/6)=1/4

P(EO)=1-1/4-1/4=1/2

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A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate
neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:  

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate  munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

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We are also told if he instead added 4  glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

C=\frac{1}{7}*(C+D+4)...(2)

Upon substituting C's value from equation (2) in equation (1) we will get,

\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)

Let us have a common denominator on right side of equation.

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11*(C+D-10)=11*\frac{7}{11}*(C+D-2)  

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(C+D)=24

Therefore, the total number of Munchkins in original box is 24.

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