Can you take a better pic? and nukber 1 is supplemntary so it is half
3x + 5 > 11
3x + (5 - 5) > 11 - 5
3x > 6
3x / 3 > 6 / 3
x > 2
x - 3 < 1
x (-3 + 3) < 1 + 3
x < 4
When subtracting / adding values to both sides, the inequality does not change.
When multiplying / dividing by a positive value, the inequality also doesn't change, but when multiplying , dividing with a negative value, the inequality must be flipped.
Answer:
The answer would be Equation B:
x2 - 8x + 41
Step-by-step explanation:
Step-by-step explanation:
part A:
ABCD is transformed to obtain figure A′B′C′D′:
1) by reflection over x-axis, obtain the image :
A(-4,-4) B(-2,-2) C(-2, 1) D(-4, -1)
2) by translation T (7 0), obtain the image :
A'(3,-4) B'(5,-2) C'(5, 1) D'(3, -1)
part B:
the two figures are congruent.
the figures that transformed by reflection either or translation will obtain the images with the same shape and size (congruent)
Answer:
28 different ways
Step-by-step explanation:
This is a combination question. Combination has to do with selection.
Total number of element in the set = 8
Number divisible by 6 or 8 are {-98, -48, -42, -36, -18, -6}
Total number divisible by 6 or 8 is 6
The number of ways we can choose 6 items from 8 is expressed as;
8C6 = 8!/(8-6)!6!
8C6 = 8!/(2)!6!
8C6 = 8*7*6!/2!6!
8C6 = 8*7/2
8C6 = 56/2
8C6 = 28 ways
Hence there are 28 different ways
