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damaskus [11]
3 years ago
15

E pls help me again

Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

D

Step-by-step explanation:

14.34 x 21 - 2.40 x 7 = 284.55

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Could anyone help me answer this​
BARSIC [14]

Answer:

the answer might be 150 ft

Step-by-step explanation:

adds on 30

hope that helps

please mark as brainliest if correct

thank you

19NBoli

3 0
3 years ago
4. A mountain climber needs to descend 2,000 feet.
DENIUS [597]

Answer:

C. 500 ft

Step-by-step explanation:

If we want to make it all equal, we can divide the 2,000 ft by 4 because we have 4 equal descents.

2000 ÷ 4 = 500

He should travel <u>500 feet</u> in each descent.

8 0
3 years ago
On the same day at school, 1/6 of the students were wearing skirts and 5/8 of the students were wearing pants. The rest of the s
anastassius [24]
What you do is you find the common denominator between the two fractions given.  the easiest is to just multiply them 

6*8=48

and then multiply each numerator by the number it's denominator is multiplied by

1*8=8  and 5*6=30

and now you have your new fractions, add them together

8/48+30/48=38/48

this leaves 10/48 as the people who were wearing shorts,  just simplify this and it's done

10/2    =5/24
48/2
4 0
3 years ago
Read 2 more answers
Real Estate One conducted a recent survey of house prices for properties located on the shores of Tawas Bay. Data on 26 recent s
Ivanshal [37]

Answer:

Step-by-step explanation:

Hello!

Given the data for the variables:

Y: Selling price of a house on the shore of Tawas Bay

X₁: Number of bathrooms of a house on the shore of Tawas Bay.

X₂: Square feet of a house on the shore of Tawas Bay.

X₃: Number of bedrooms of a house on the shore of Tawas Bay.

The multiple regression model is Y= α + β₁X₁ + β₂X₂ + β₃X₃ + εi

a. Using software I've entered the raw data and estimated the regression coefficients:

^α= a= -5531.01

Represents the mean selling price of the houses when 0 bathrooms, 0 square feet and 0 bedrooms.

^β₁= b₁= -1386.21

Represents the modification of the mean selling price of the houses when the number of bathrooms increases in one unit and the square feet and number of bedrooms remain unchanged.

^β₂= b₂= 60.28

Represents the modification of the mean selling price of the houses when the square feet increase in one unit and the number of bathrooms and bedrooms remain unchanged.

^ β₃= b₃= 54797.08

Represents the modification of the mean selling price of the houses when the number of bedrooms increase in one unit and the number of bathrooms and square feet of the houses remain unchanged.

^Y= -5531.01 -1386.21X₁ + 60.28X₂ + 54797.08X₃

b)

R²= 0.55

R²Aj= 0.49

The coefficient of determination gives you an idea of how much of the variability of the dependent variable (Y) is due to the explanatory variables. Each time you add another explanatory variable to the regression the coefficient increases regarding of real contribution of the new variable. This could lead to thinking (wrongly) that the new variables are good to explain the dependent variable.  

The adjusted coefficient of determination is a correction made to the raw coefficient of determination to have a more unbiased estimation of the effect the independent variables have over the dependent variable.

⇒ As you can see both coefficient are around 50%, which means that these explanatory variables

c)

The standard error estimate, this is the estimate of the population variance of the errors. In the ANOVA is represented by the Mean Square of the errors (MME)

Se²= MME= 3837640577.01

Se= 61948.6931

d) and f)

For the hypotheses tests for each slope the t- and p-values are:

α: 0.05

β₁: t_{H_0}= \frac{b_1-\beta_1 }{Sb_1} t= -0.06; p-value: 0.9528 ⇒ Do not reject H₀, the test is not significant.

β₂: t_{H_0}= \frac{b_2-\beta_2 }{Sb_2} t= 2.56; p-value: 0.0180 ⇒ Reject H₀, the test is significant.

β₃: t_{H_0}= \frac{b_3-\beta_3 }{Sb_3} t= 2.28; p-value: 0.0326 ⇒ Reject H₀, the test is significant.

e)

H₀: β₁= β₂= β₃

H₁: At least one βi is different from the others ∀ i=1, 2, 3

α: 0.05

F= 9.03

p-value: 0.0004

⇒ Reject H₀, the test is significant.

I hope it helps!

5 0
3 years ago
Carl ordered a package that weighs 192 pounds. It was shipped to him inside a box and surrounded by packing material. The total
AURORKA [14]

Answer:

The weight of box and pocking material =13 pound

Step-by-step explanation:

Let the weight of box and packing material =x

weight of package =192 pounds

total weight =205 pound

x+192=205

Subtract both side by 192

x+192-192=205-192\\x+0=13\\x=13

Hence weight of box and packing material =13 pound

7 0
3 years ago
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