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Andre45 [30]
3 years ago
14

How do you describe the milk?

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer:

emulsion

Explanation:

An emulsion is a mixture of two or more liquids that are normally immiscible. Emulsions are part of a more general class of two-phase systems of matter called colloids.

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A balloon is floating around outside your window. The temperature outside is 21 ∘C , and the air pressure is 0.700 atm . Your ne
Andreyy89

Answer:

V=162L

Explanation:

Hello,

In this case, we can compute the required volume by using the ideal gas equation as shown below:

PV=nRT

Thus, solving for the volume and considering absolute temperature (in Kelvins), we obtain:

V=\frac{nRT}{P}= \frac{4.70mol*0.082\frac{atm*L}{mol*K}*(21+273)K}{0.700atm} \\\\V=162L

Best regards.

4 0
3 years ago
Overall do you think photosynthesis is endothermic or exothermic
blondinia [14]

Answer:

Endothermic hope that helps

Explanation:

6 0
3 years ago
Consider the first-order reaction shown here. the yellow spheres in the pictures to the right represent the reactant,
Luda [366]
The rate constant of the reaction K we can get it from this formula:

K=㏑2/ t1/2 and when we have this given (missing in question):
that we have one jar is labeled t = 0 S and has 16 yellow spheres inside and the jar beside it labeled t= 10 and has 8 yellow spheres and 8 blue spheres and the yellow spheres represent the reactants A and the blue represent the products B

So when after 10 s  and we were having 16 yellow spheres as reactants and becomes 8 yellow and 8 blue spheres as products so it decays to the half amount so we can consider T1/2 = 10 s
a) by substitution in K formula:
∴ K = ㏑2 / 10 = 0.069 
The amount of A (the reactants) after N half lives = Ao / 2^n
b) so no.of yellow spheres after 20 s (2 half-lives) =  16/2^2 = 4
and the blue spheres = Ao - no.of yellow spheres left = 16 - 4 = 12
c) The no.of yellow spheres after 30 s (3 half-lives) = 16/2^3 = 2
and the blue spheres = 16 - 2 = 14

8 0
3 years ago
Given the following reaction: H2SO4+2LiOH=Li2SO4+2H20, what mass of water is produced from 19 g of sulfuric acid?
goldfiish [28.3K]

Hi,

To solve the question, first of all we will find out the no. of moles of H2SO4 in  19 g of sulfuric acid.

As we know:

              No . of moles = Mass/ Molar mass

              No. of moles= 19 g/98.08 g

               No. of moles= 0.1937

Now we know the no of moles of H2SO4 that will react with 2LiOH. We also know the  molar equivalence of H2SO4 , and 2LiOH that will react.

So, the  water that will be produced will be 2H2O and 1 Li2SO4 when H2SO4 that will react with 2LiOH.

                          0.1937 x 2x 18.01

                                 =6.977

                                  =6.98

Therefore, approximately 6.98 grams of water will be produced from 19 g of sulfuric acid.


Hope it helps!


5 0
3 years ago
Level 1: 2Sr + 02 > 2Sro
tekilochka [14]

Answer:

Sr would be the limiting reactant

5 moles

Explanation:

Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.

Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.

Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.

From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.

When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.

For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.

8 0
3 years ago
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