We are given a line with the following data:
r-value = 0.657 (r)
standard deviation of x-coordinates = 2.445 (Sx)
standard deviation of y-coordinates = 9.902 (Sy)
We are asked to find the slope of the line up to 3 decimal places.
To find the slope of the line, based on the data that we have, we can use this formula:
slope, b = r * (Sy / Sx)
substitute the values to the formula:
b = 0.657 * ( 9.902 / 2.445 )
Solve for the b.
Therefore, the slope of the line is
b = 2.66078, round off to three decimal places:
b = 2.661 is the slope of the line.
Answer:
(-12, -12)
Step-by-step explanation:
Since the scale factor is 3, you would multiply the x-coordinate and y-coordinate by it.
-4×3=-12
Hope this helps!!
Just Reach this number to its simplest form
as=80/56
=10/7
SIMPLEST FORM=10/7
RATIO=10:7
Answer:
The 95% confidence interval = (98.225, 98.655)
Step-by-step explanation:
The formula for Confidence Interval =
Mean ± z × standard deviation/√n
Where Mean = 98.44°F
Standard deviation = 0.30°F
n = number of samples is 10
Because our number if samples is small, we use the t score confidence interval formula
Mean ± t × standard deviation/√n
Degrees of Freedom = n - 1
= 10 - 1 = 9
We find the t score of 95% confidence interval and degrees of freedom 9
= 2.262
Hence,
Confidence interval = 98.44 ± 2.262 × 0.30/√10
= 98.44 ± 0.214592162
Confidence Interval
98.44 - 0.214592162
= 98.225407838
≈ 98.225
98.44 + 0.214592162
= 98.654592162
≈ 98.655
The 95% confidence interval = (98.225, 98.655)
