Expand and simplify 3(C - 2d) - 2(2C - 3d).
2 answers:
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Answer:
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Answer:
We conclude that commute time in her city is less than the amount reported by the survey which is 25.4 minutes.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 25.4 minutes
Sample mean, = 22.1 minutes
Sample size, n = 15
Alpha, α = 0.10
Sample standard deviation, s = 5.3 minutes
First, we design the null and the alternate hypothesis
We use one-tailed t(left) test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
Thus, there is enough evidence to conclude that commute time in her city is less than the amount reported by the survey which is 25.4 minutes.
Answer: They should order 160 steak, 80 lobster and 260 chicken. The total cost for the meals would be $4460
Step-by-step explanation:
The cruiser will have 400 passangers on board. By taking into account that the cruise line decided to buy 25% more of meals than bookings, we can conclude that in order to calculate the ammount of meals they will order, we have to take the number of passangers on board, 400, and add to it 25% more. So the number of meal orders will be 400 + (1/4 * 400) = 500.
Let's use the letter S to simbolize the ammount of steak they should buy, with L the ammount of lobster, and with C the ammount of chicken. The sum of those ammounts should be 500, so we deduce this formula
we can replace C with 500 - S - L. Since at least forty percent of the passangers will have steak dinner and at least twenty percent will have lobster, we obtain this relations:
We note the total cost of the meals (in $). The value of
will depend on the values of S and L. Using the information we are given about the cost of each dinner, and recalling that C was 500- S - L, we can represent
by this formula
Which is equal to
We want to minimaze the value of , since 3*S + 6*L will get bigger as we use bigger values of S and L, then we will be in a good position if we take the values of S and L as low as possible.
With the restriction we obtained, the lowest values of S and L we can take are 160 and 80 respectively; so we take those values. In conclusion
- S = 160 (number of steak)
- L = 80 (number of lobster)
- C = 500-160-80 = 260 (number of chicken)
The total cost of the meals is