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valkas [14]
3 years ago
8

Ammonia and sulfuric acid react to form ammonium sulfate. Determine the starting mass of each reactant if 20.3 g of ammonium sul

fate is produced and 5.89g of sulfuric acid remains unreacted.

Chemistry
1 answer:
strojnjashka [21]3 years ago
8 0
Hope you are able to see

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What is atom.
katovenus [111]

Answer:

atom is the smallest indivisible particle of an element

Explanation:

The symbol of 20 element are H He li Be B C N O F Ne Na Mg Al Si P S Cl Ar K Ca

element is the simplest pure form of a substance .

3 0
2 years ago
water from a town is suspected to contain chloride ions but not sulphate ions . describe how the presence of the chloride ions i
andreyandreev [35.5K]

Answer:

See Explanation

Explanation:

The presence of chloride ions in water can be established by adding dilute trioxonitrate V acid to a sample of the water in drops followed by aqueous silver trioxonitrate V.

If a white precipitate is formed, which is soluble in excess aqueous ammonia solution, then the presence of chloride ion in the water sample is ultimately confirmed.

3 0
3 years ago
N₂ + 3H2 → 2NH3
Rainbow [258]

Answer:

187 moles NH₃

Explanation:

To find the amount of ammonia formed, you need to multiply the given value by the mole-to-mole ratio consisting of both relevant molecules. The mole-to-mole ratio is made up of the molecules' coefficients in the balanced equation. The desired unit should be placed in the numerator of the ratio. The final answer should have 3 sig figs to reflect the lowest amount of sig figs among the given values.

1 N₂ + 3 H₂ ----> 2 NH₃
^                         ^

93.5 moles N₂          2 moles NH₃
----------------------  x  -------------------------  =  187 moles NH₃
                                    1 mole N₂

3 0
2 years ago
Read 2 more answers
. Calculate the molality of each of the following solutions: (a) 0.710 kg of sodium carbonate (washing soda), Na2CO3, in 10.0 kg
Step2247 [10]

Answer:

a)0.67 molal

b) 5.67 molal

c) 2.82 molal

d) 0.0268 molal

Explanation:

Step 1: Data given

Molality = moles solute / mass solvent

(a) 0.710 kg of sodium carbonate (washing soda), Na2CO3, in 10.0 kg of water—a saturated solution at 0°C

Calculate moles of Na2CO3 =  710 grams / 105.99 g/mol = 6.70 moles

Molality = 6.70 moles / 10 kg = 0.67 molal

(b) 125 g of NH4NO3 in 275 g of water—a mixture used to make an instant ice pack

Calculate moles of NH4NO3 = 125 grams / 80.04 g/mol = 1.56 moles

molality = 1.56 moles / 0.275 kg = 5.67 molal

(c) 25 g of Cl2 in 125 g of dichloromethane, CH2Cl2

Calculate moles Cl2 = 25 grams / 70.9 g/mol= 0.353 moles

Molality = 0.353 moles / 0.125 kg = 2.82 molal

0.372 g of histamine, C5H9N, in 125 g of chloroform, CHCl3

Calculate moles histamine = 0.372 grams / 111.15 g/moles = 0.00335 moles

Calculate molality = 0.00335 moles / 0.125 kg = 0.0268 molal

NOTE: histamine is C5H9N3 not C5H9N

4 0
3 years ago
Convert the following: 100 hg(hectograms) to g(grams)
solniwko [45]

Answer:

A

Explanation:

10,000g

just multiply the amount of hectograms by 100 to get grams

4 0
3 years ago
Read 2 more answers
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