Answer:
The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 7
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.3246
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg
The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg
The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).
Half of 6 is 3
Half of 8 is 4
so it will be 3 in by 4 in.
Answer:
Mean = 3.4
Variance = 1.088
Standard deviation = 1.0431
Step-by-step explanation:

The mean of a binomial distribution with parameters N (the number of trials) and p (the probability of success for each trial) is 
Thus,

The variance of the binomial distribution is
, where
is the variance of the binomial distribution, so

The standard deviation
is the square root of the variance
so

The answer is 1/4. Hope I could help! :D
Step 1: set up equation
-2x+y=3
Step 2: add 2x to both sides
-2x+y=3
+2x +2x
<u>
y=3+2x</u>
Hope this helps :)