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1 answer:
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Answer:
(3, 1)
Step-by-step explanation:
Given the following constraints:
2x + 4y ≤ 10
x + 9y ≤ 12
x ≥ 0
y ≥ 0
We have to first graph the above constraints and secondly, we find the boundary points for the feasible region. This is done by plotting the graphs of 2x + 4y ≤ 10 and x + 9y ≤ 12.
From the graph, the following points satisfy the constraints:
(0,0) , (3,1) , (0,4/3) , (5,0)
Given that:
P = x + 6y
For (0, 0): P = x + 6y = 0 + 6(0) = 0
For (3, 1): P = x + 6y = 3 + 6(1) = 9
For (0, 4/3) P = x + 6y = 0 + 6(4/3) = 8
For (5, 0) P = x + 6y = 5 + 6(0) = 5
Answer:
30
Step-by-step explanation:
To find the determinant of a 3x3 matrix, you can use this method. (See picture.)
Start with the first number in the top row, and block off the row and column. A 2x2 matrix will be left. Find the determinant of this 2x2 matrix, and multiply it by the number in the top row.
Repeat for the other two numbers in the top row. Add the first result, subtract the second, and add the third.
det A = -2 [(3)(-5) − (a)(0)] − 2 [(0)(-5) − (a)(0)] + b [(0)(0) − (3)(0)]
det A = -2 (3)(-5) − 0 + 0
det A = 30
