F(x)=x-3 I think but I am not sure
Answer:
The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
Step-by-step explanation:
The average speed is given by the following equation:

From 10A.M. to noon.
You traveled at 50mph during 2 hours. So how long you traveled?



You traveled 100 miles.
What was your average speed over the time interval from 9 A.M. to noon
From 9 A.M. to 10 A.M, you did not travel.
From 10 P.M. to noon, 100 miles.
So 100 miles during 3 hours.

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
H= -55t + 3000. Hope this helps!
the question says that the samples included 100 people each, so it's just 100 multiplied by the amount of samples:
7×100=700
Answer
given,
work = 5 J
spring stretch form 30 cm to 39 cm

x = 0.39 - 0.30 = 0.09 m


k = 1234.568 N/m
a) work when spring is stretched from 32 cm to 34 cm
x₂= 0.34 -0.30 = 0.04 m
x₁ = 0.32 - 0.30 = 0.02


W = 0.741 J
b) F = k x
25 = 1234.568 × x
x = 0.0205 m
x = 2.05 cm