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3 years ago

Who is he heeeelp i really need help

Mathematics

2 answers:

olasank [31]3 years ago

8 0

Answer:

Albert Einstein

Step-by-step explanation:

Elena-2011 [213]3 years ago

6 0

Step-by-step explanation:

Albert Einstein. hope it helps

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HELPPP idk what the answer is

Arada [10]

Answer:

what is the question

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

3 years ago

WILL MARK BRAINLIEST!! please answer all questions

lana66690 [7]

Answer:

1a) −24x^4−52x^3+198x^2+126x−325

2a) 14x^2+7x−41

3a) 30x^3+9x^2+32x−7

Step-by-step explanation:

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3 years ago

Rearrange x = 3g + 2 to make g the subject

lord [1]

Answer:

$g=\frac{x}{3} -\frac{2}{3}$

Step-by-step explanation:

You divide 3 from both sides leaving you with g=(x/3)-(2/3)

Please mark my answer as brainlyest.

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3 years ago

Which is the correct order for the side lengths from shortest to longest?

nexus9112 [7]

68°+52°=120 and a triangle is 180° so 180-120=60 so x=60

shortest to greatest 52, 60, 68

3 0

3 years ago

Who is he heeeelp i really need help​

Who is he heeeelp i really need help