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Luba_88 [7]
3 years ago
6

Determine the number of moles of gas contained in a 1.25 L container at 25 degrees Celsius and 800 torr

Chemistry
1 answer:
tiny-mole [99]3 years ago
8 0
You would have to use the ideal gas law: PV = nRT where,

P = pressure
V = volume
n = moles
R = universal gas constant for a specific pressure (in this case it's 62.364 torr)
T = temperature in Kelvin

First, convert Celsius to kelvin by adding 273 to 25, which gives you 298K

Now plug in your variables to find n:

(800 torr)(1.25 L) = n(62.364)(298K)

1000 = 18584.472n

Now divide 1000 by 18584.472 to get n:

1000/18584.472 = 0.054 moles
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The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3
Oksanka [162]

Answer : The mass of NaN_3 required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = 113 L

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 85^oC=273+85=358K

Putting values in above equation, we get:

1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K

n=3.84mol

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 3 mole of N_2 produced from 2 mole of NaN_3

So, 3.84 moles of N_2 produced from \frac{2}{3}\times 3.84=2.56 moles of NaN_3

Now we have to calculate the mass of NaN_3

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

Molar mass of NaN_3 = 65 g/mole

\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g

Therefore, the mass of NaN_3 required is, 166.4 grams.

3 0
3 years ago
Balancing
Kruka [31]
2 in front of H2. Technically nothing in front of O2 otherwise put a 1 then a 2 in front of H2O

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5 0
3 years ago
How many nucleons are there in an atom with a nuclear charge of +20 and 23 neutrons?
dalvyx [7]

Answer:

43

Explanation:

8 0
3 years ago
Imagine that you have an ideal gas in a 6.70 L container, and that 1450 molecules of this gas collide with a square-inch area of
kakasveta [241]

Answer:

they could collide 241.66 molec / in² by increasing the volume to 40.2L

Explanation:

ideal gas:

<u>Boyle Law</u>: at constant temperature the pressure of a gas varies inversely with the volume

  • V1 * P1 = V2 * P2
  • P = F / A

∴ V1 = 6.70 L;

∴ P1 = 1450 molec / in²

∴ V2 = 40.2 L

⇒ P2 = (( 6.70 L ) * ( 1450 molec/in²)) / 40.2 L

⇒ P2 = 241.66 molec/in²

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What causes clothes from a dryer to stick together?
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Different fabrics rub together, and electrons may rub off 
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